SQL SERVER-查询爆破sa密码的主机

drop table if exists #sql

create table #sql

(

Logdatae varchar(50),

processinfo varchar(50),

[text] varchar(max)

)

go

INSERT INTO  #sql

Exec xp_readerrorlog 0

Go

SELECT distinct right(text,16)FROM #sql  WHERE Logdatae like  'Apr 17 2019%'

AND text LIKE 'Login failed for user ''sa''. Reason: Password did not match that for the login provided%'