该符号的直角三角形，边长等于该数字

问题描述

您好。我对C语言有疑问。正在进行的程序是一个程序，它输出该符号的直角三角形，边长等于该数字。如果输入0，程序将终止，否则将再次请求新输入。这是我的代码：







所以我的问题是如果输入0，如何终止否则它会再次要求新输入。

我知道我可能需要使用while循环。但是我该怎么改呢？



我尝试过的事情：

  #include   <     assert.h    >  
   #include   <     stdio.h    >  
   #include   <     stdlib.h    >  
  
  int  m ain（）
 {
  char  s;  / *   s是符号（输入）* /  
  int  a，b，n;  / *   n是行数（输入）* /  
 
 printf （ 请输入三角形的符号：... \ n）;  / *  请求符号输入* /  
 scanf_s（ ％c，& s， 1 ）; 
 printf（ 请输入5到35之间的正非零数字：... \ n ）;  / *  询问输入的行数* /  
 scanf_s（ ％d，& n）; 
断言（n> =  5 && n< =  35 ）; 
 
 
  for （a =  1 ; a< = n; a ++） / *  要显示的行数+创建* /  
 {
  for （b =  1 ; b< = a; b ++）
 {
 printf（ ％c，s）; 
} 
 printf（  \ n）; 
} 
 system（  PAUSE）; 
} 

解决方案

你的程序可能有一些键盘缓冲区，第一个scanf只吃它。

Hello. I have a question on C language. The program im working on is a program that outputs a right angle triangle of that symbol with sides equal to that number. Program terminates if you enter 0 otherwise it will ask for a new input again. Here is my code:



So my question is that "HOW to terminates if you enter 0 otherwise it will ask for a new input again. "
I know I probably need to use while loop. But how do i change it?

What I have tried:

#include < assert.h >
#include < stdio.h >
#include < stdlib.h >

int main()
{
	char s;			/*s is symbol (the input)*/
	int a, b, n;	/*n is number of rows (the input)*/

	printf("Please type the symbol of the triangle:...\n");	/*Ask for symbol input*/
	scanf_s("%c", &s, 1);
	printf("Please type a positive non-zero number between 5 and 35:...\n"); /*Ask for number of rows input*/
	scanf_s("%d", &n);
	assert(n >= 5 && n <= 35);


	for (a = 1; a <= n; a++)/*How many rows to display+create*/
	{
		for (b = 1; b <= a; b++)
		{
			printf("%c", s);
		}
		printf("\n");
	}
	system("PAUSE");
}

解决方案

Your program have probably something in keyboard buffer and the first scanf just eat it.

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