本文介绍了ptree get_value,其名称包括“.".的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
"A": "1"
"A.B": "2"
"A.C": "3"
如果我通过ptree进行迭代,如何获取 A.B
的值.如果我尝试以获得 pt.get_child("A \ .B").get_value< std :: string>()
的值.我收到以下异常
How to get the value of A.B
if i iterate through the ptree it works. if i try to get value of pt.get_child("A\.B").get_value<std::string>()
. i get the following exception
terminate called after throwing an instance of boost::exception_detail::clone_impl<boost::exception_detail::error_info_injector<boost::property_tree::ptree_bad_path> >'
what(): No such node
请在下面找到完整的代码
please find the complete code below
#include <boost/property_tree/ptree.hpp>
#include <boost/property_tree/ini_parser.hpp>
#include <iostream>
#include <string>
#include <iterator>
using boost::property_tree::ptree;
/* Indent Json Output */
std::string indent(int level) {
std::string s;
for (int i = 0; i < level; i++) s += " ";
return s;
}
/* Print tree in json format */
void printTree(ptree & pt, int level) {
if (pt.empty()) {
std::cerr << "\"" << pt.data() << "\"";
} else {
if (level) std::cerr << std::endl;
std::cerr << indent(level) << "{" << std::endl;
for (ptree::iterator pos = pt.begin(); pos != pt.end();) {
std::cerr << indent(level + 1) << "\"" << pos-> first << "\": ";
printTree(pos->second, level + 1);
++pos;
if (pos != pt.end()) {
std::cerr << ",";
}
std::cerr << std::endl;
}
std::cerr << indent(level) << " }";
}
return;
}
int main()
{
ptree pt;
read_ini("sample.ini", pt);
printTree(pt, 0);
std::cout << pt.get_child("A.B").get_value<std::string>() << std::endl; //tries to resolve A.B to two nodes
std::cout << pt.get_child("A\\.B").get_value<std::string>() << std::endl; //error
}
sample.ini
sample.ini
A=1
A.B=2
A.C=3
推荐答案
您可以使用替代路径定界符,但这有点棘手,而且没有很好的记录.
You can use alternative path delimiters, but it's a bit tricky and not very well documented.
您必须临时指定备用路径分隔符:
You have to temporarily specify an alternative path separator:
#include <boost/property_tree/ini_parser.hpp>
#include <iostream>
using boost::property_tree::ptree;
int main() {
ptree pt;
pt.put("a.b", "first");
pt.put(ptree::path_type("a|complicated.name", '|'), "second");
write_ini(std::cout, pt);
}
打印
[a]
b=first
complicated.name=second
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