本文介绍了如何组合sql Count查询的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

select t.TruckNo ,count(jt.JobID)as OnTimekpi
 from tbl_pms_JobOrders_Trucks_Info jt
inner join tbl_pms_JobOrders j on j.JobID = jt.JobID
Inner Join tbl_pms_Trucks t on t.TruckID=jt.TruckID
Inner Join tbl_pms_ShipmentInfo si on si.ShipmentID = jt.ShipmentID
Inner Join tbl_pms_DeliveryInfo d on d.JobID=j.JobID
where  j.WarehouseID=225 and j.Planneddate between '20131201' and '20140131' and t.TruckID != 312 and t.IsDeleted != 'true'
       and jt.ETA >= d.DeliveryTime
       group by  t.TruckNo,jt.StausCode

       select t.TruckNo,COUNT(jt.JobID)as OFFTimekpi from tbl_pms_JobOrders_Trucks_Info jt
inner join tbl_pms_JobOrders j on j.JobID = jt.JobID
Inner Join tbl_pms_Trucks t on t.TruckID=jt.TruckID
Inner Join tbl_pms_ShipmentInfo si on si.ShipmentID = jt.ShipmentID
Inner Join tbl_pms_DeliveryInfo d on d.JobID=j.JobID
where  j.WarehouseID=225 and j.Planneddate between '20131201' and '20140131' and t.TruckID != 312 and t.IsDeleted != 'true'
       and jt.ETA < d.DeliveryTime group by t.TruckNo,jt.StausCode









注意:从First Select声明我得到31条记录,从Second得到17条记录



谢谢提前





Note: From First Select statement i got 31 records and from Second i got 17 records

Thanks advance

推荐答案

and jt.ETA >= d.DeliveryTime




and jt.ETA < d.DeliveryTime

由于每个都排除了另一个,你可以完全删除条件并获得所有结果。

Since each excludes the other, you can remove teh condition completely and get all the results.


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09-27 02:32