本文介绍了C ++:宏可以扩展“abc”成'a','b','c'?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我写了一个可变参数模板来接受 char
参数的可变数,例如
I've written a variadic template that accepts a variable number of char
parameters, i.e.
template <char... Chars>
struct Foo;
我只是想知道是否有任何宏观技巧,将允许我实例化这个语法类似于以下内容:
I was just wondering if there were any macro tricks that would allow me to instantiate this with syntax similar to the following:
Foo<"abc">
或
Foo<SOME_MACRO("abc")>
或
Foo<SOME_MACRO(abc)>
等。
基本上,
Foo<'a', 'b', 'c'>
这对我来说不是一个大问题,因为它只是一个玩具程序,
This isn't a big issue for me as it's just for a toy program, but I thought I'd ask anyway.
推荐答案
我今天创建了一个,并在GCC4.6.0上测试。
I've created one today, and tested on GCC4.6.0.
#include <iostream>
#define E(L,I) \
(I < sizeof(L)) ? L[I] : 0
#define STR(X, L) \
typename Expand<X, \
cstring<E(L,0),E(L,1),E(L,2),E(L,3),E(L,4), E(L,5), \
E(L,6),E(L,7),E(L,8),E(L,9),E(L,10), E(L,11), \
E(L,12),E(L,13),E(L,14),E(L,15),E(L,16), E(L,17)> \
cstring<>, sizeof L-1>::type
#define CSTR(L) STR(cstring, L)
template<char ...C> struct cstring { };
template<template<char...> class P, typename S, typename R, int N>
struct Expand;
template<template<char...> class P, char S1, char ...S, char ...R, int N>
struct Expand<P, cstring<S1, S...>, cstring<R...>, N> :
Expand<P, cstring<S...>, cstring<R..., S1>, N-1>{ };
template<template<char...> class P, char S1, char ...S, char ...R>
struct Expand<P, cstring<S1, S...>, cstring<R...>, 0> {
typedef P<R...> type;
};
一些测试
template<char ...S>
struct Test {
static void print() {
char x[] = { S... };
std::cout << sizeof...(S) << std::endl;
std::cout << x << std::endl;
}
};
template<char ...C>
void process(cstring<C...>) {
/* process C, possibly at compile time */
}
int main() {
typedef STR(Test, "Hello folks") type;
type::print();
process(CSTR("Hi guys")());
}
所以当你没有得到一个 ','b','c'
,仍然会获得编译时字符串。
So while you don't get a 'a', 'b', 'c'
, you still get compile time strings.
这篇关于C ++:宏可以扩展“abc”成'a','b','c'?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!