Javascript将$ _FILE ['file']发布到php

本文介绍了Javascript将$ _FILE ['file']发布到php的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 有人可以帮我解决这个问题，我试图改变我的文件上传方案以使用JavaScript，这样我的页面就不会在用户上传文件时提交，谢谢你提前; belove ismy code < script type = text / javascript > 功能fileUplodBtn（fileID）{ $（'＃'+ fileID）.trigger（'click'）; // alert（fileID）; } 函数fileUploder（fileID）{ //document.getElementById（'addrec'）。submit（）; // var formData = new FormData（$（＃myForm）。[0]）; //$.post('AddFormLogic.php'，formData，function（response） var fileInput = document.getElementById（uploadrecipephoto）; $ .post（ upload.php，{uploadrecipephoto：'uploadrecipephoto'}，函数（数据）{ alert（data）; }）; alert（fileInput .files [0] .size）; alert（fileInput.value）; alert（'得到它'）; } < / script > < div id = response > < / div > < 输入 type = file id = uploadrecipephoto value = uploadfile 名称 = file style = visibility：hidden / > < tr > < th align = left > < 输入 类型 = 提交 class = btnLogin name =' btnCreateRecipe' value = 创建配方 / > < / th > < th class = file-upload 对齐 = right > < div id =' file_browse_wrapper' type = 提交 onclick = return false onmousedown = javascript：fileUplodBtn（'uploadrecipephoto'）; > < 输入 type = 隐藏 name = uploadrecipephoto value = recipephoto > < / div > < / th > < / tr > 和我的PHP方面我有捕手 if （isset（$ _ FILES [' file'] [' name']））{ getrecphoto（ ）; $ fileloc = $ _SESSION [' temprecimg']; echo $ fileloc ; echo ' ------ --------'。$ _ SESSION [' ufolder']; echo ' ++++++ +++'。$ _ FILES [' file'] [' type']; echo ' < script type =文本/ JavaScript的>警报（ 22222222）; < /脚本>'; } 我一直试图解决这个问题3天了！我知道这看起来很愚蠢，但我不知道如何将文件信息发布到php 解决方案 （'＃'+ fileID）.trigger（'click'） ; // alert（fileID）; } 函数fileUploder（fileID）{ //document.getElementById（'addrec'）。submit（）; // var formData = new FormData（ （＃myForm）。[0]）; // .post（'AddFormLogic.php'，formData，function（response） var fileInput = document.getElementById（uploadrecipephoto ）; can someone please help me with this code, Im trying to change my file upload scheme to use JavaScript so that my page doesnt get submitted ever time user uploads a file, THANK YOU IN ADVANCE; belove ismy code<script type="text/javascript"> function fileUplodBtn(fileID) { $('#'+fileID).trigger('click'); //alert(fileID); } function fileUploder(fileID) { //document.getElementById('addrec').submit(); //var formData = new FormData($("#myForm").[0]); //$.post('AddFormLogic.php', formData, function(response) var fileInput = document.getElementById("uploadrecipephoto"); $.post("upload.php",{uploadrecipephoto: 'uploadrecipephoto'}, function(data) { alert(data); }); alert(fileInput.files[0].size); alert(fileInput.value); alert('got it'); }</script> <div id="response"></div><input type="file" id="uploadrecipephoto" value="uploadfile" name="file" style="visibility: hidden" /><tr > <th align="left" > <input type="submit" class="btnLogin" name='btnCreateRecipe' value="Create Recipe" /> </th> <th class="file-upload" align="right"> <div id='file_browse_wrapper' type="submit" onclick="return false" onmousedown="javascript:fileUplodBtn('uploadrecipephoto');" > <input type="hidden" name="uploadrecipephoto" value="recipephoto"> </div> </th></tr>and on my PHP side I have the catcher if (isset($_FILES['file']['name'])){ getrecphoto(); $fileloc= $_SESSION['temprecimg']; echo $fileloc; echo '--------------'.$_SESSION['ufolder']; echo '+++++++++'.$_FILES['file']['type']; echo '<script type="text/javascript"> alert("22222222"); </script>';}I have been trying to figure this out for 3 days now! I know it seems dumb but i just cant figure outhow to post the File info to the php 解决方案 ('#'+fileID).trigger('click'); //alert(fileID); } function fileUploder(fileID) { //document.getElementById('addrec').submit(); //var formData = new FormData(("#myForm").[0]); //.post('AddFormLogic.php', formData, function(response) var fileInput = document.getElementById("uploadrecipephoto"); 这篇关于Javascript将$ _FILE ['file']发布到php的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！