问题描述
from django.core.exceptions import FieldError
#This is a method of a class
def _order_item_list(self, item_list, order_items_by, previous_order_by):
if order_items_by == previous_order_by:
order_items_by = '-' + order_items_by
try:
result = item_list.order_by(order_items_by)
except FieldError:
result = item_list
return result, order_items_by
现在,当我按照生成的链接后的有效字段进行排序时,一切都可以正常运行。当我编辑链接并添加一些虚拟字段名以进行排序时,此异常应将其捕获,并应返回原始列表。但这并没有发生,相反,我总是从Django收到FieldError。
Now when I order by valid fields following the generated link,everything works perfect. When I edit a link and add some dummy fieldnames for ordering, it should be catched by this exception and the original list should be returned. But it is not happening, instead I always get a FieldError from django.
FieldError at ...
FieldError at ...
无法将关键字u'fgsdffds'解析为字段。选择包括:...
Cannot resolve keyword u'fgsdffds' into field. Choices are: ...
推荐答案
这表示存在错字,否则在其他地方会发生异常。插入调试行:
This means there's a typo, or the exception happens elsewhere. Insert a debug line:
import pdb; pdb.set_trace()
,然后看看如何执行代码。尝试或调试器,而不是标准的调试器。当您拥有调试器时,许多问题都会消失,并且可以确切地看到出了什么问题。
before the try-except and see how the code is executed. Try PUDB or IPDB debuggers instead of the standard one. Many questions disappear when you have a debugger and can see exactly what goes wrong.
这篇关于django order_by FieldError异常无法捕获的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!