本文介绍了所述值尚未设定值的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
Module Module1
Sub Main()
Dim firstName As String
Dim lastName As String
Dim pointsReceived As Decimal
Dim scorePercentage As Decimal
Dim finalGrade As String
Console.WriteLine("Welcome to the Stundent Grade Calculator. This program will calculate students score percentage and grade score.")
Console.WriteLine("Please Enter students first name:")
firstName = Console.ReadLine()
Console.WriteLine("Please enter students last name:")
lastName = Console.ReadLine()
Console.WriteLine("Please enter students points received:")
pointsReceived = Console.ReadLine()
If pointsReceived >= 0 And pointsReceived <= 1000 Then
Console.WriteLine("Good Score")
Else
Console.WriteLine("Error")
End If
scorePercentage = (pointsReceived / 1000) * 100
If scorePercentage >= 0 And scorePercentage <= 59 Then
finalGrade = "F"
If scorePercentage >= 60 And scorePercentage <= 69 Then
finalGrade = "D"
If scorePercentage >= 70 And scorePercentage <= 79 Then
finalGrade = "C"
If scorePercentage >= 80 And scorePercentage <= 89 Then
finalGrade = "B"
If scorePercentage >= 90 And scorePercentage <= 100 Then
finalGrade = "A"
Else
Console.WriteLine("Error")
End If
End If
End If
End If
End If
Console.WriteLine("Student first name: " & firstName)
Console.WriteLine("Students last name: " & lastName)
Console.WriteLine("Students points: " & pointsReceived)
Console.WriteLine("Calculated Percentage: %" & scorePercentage)
Console.WriteLine("Final Grade: " & finalGrade)*/Problem is finalGrade
Console.ReadLine()
End Sub
End Module推荐答案
Dim firstName As String =""
Dim lastName As String =""
Dim pointsReceived As Decimal = 0
Dim scorePercentage As Decimal = 0
Dim finalGrade As String = "" ' this variable is not initialized with a value
Dim finalGrade As String = Nothing
这篇关于所述值尚未设定值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！