本文介绍了我收到一条评论“id返回1退出状态。我做错了什么的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
#include< stdio.h>
#include< stdlib.h> //记得如果你打算使用exit（），你需要
//这个头文件
main（）
{
//尽管是一个很长的程序，你只需要两个变量：
//第一个菜单一个，第二个菜单一个
int choice1;
int choice2;
//潜在的十年选择
printf（你想看到什么？\ n）;
printf（1. 1980年代\ n）;
printf（2. 1990年代\ n）;
printf（3。2000年代\ n）;
printf（4.Quit\\\
）;
//顶部菜单选项和使
//得到
//信息的switch语句包含在
/的do-while循环中/确保四个菜单选项中的一个
//
do
{
printf（输入您的选择：）;
scanf（％d，& choice1）;
开关（choice1）
{
//在第一种情况下，用户选择了1980年代。现在它是
//时间来查看他们需要什么具体信息。
case（1）：
{
printf（\ n你想看到什么？\ n）;
printf（1。Baseball \ n）;
printf（2.the movies\）;
printf（3.美国总统）;
printf（4.Quit\\\
）;
printf（输入您的选择：）;
scanf（％d，& choice2）;
if（choice2 == 1）
{
printf（\ n \\\
nWorld Series Chapions）;
printf（1980年代：\ n）;
printf（1980：Philadelphia Phillies\\\
）;
printf（1981：Los Angeles Dodgers \ n）;
printf（1982：St. Louis Cardinals\\\
）;
printf（1983：Baltimore Orioels \ n）;
printf（1984：Detroit Tigers \ n）;
printf（1985：Kansas City Royals \ n）;
printf（1986：New York Mets \ n）;
printf（1987：Minnesota Twins \ n）;
printf（1988：Los Angeles Dodgers \ n）;
printf（1989 Oakland A's \ n）;
printf（\ n \ nn \ n）;
休息;
}否则if（choice2 == 2）
{
printf（1980年代的\ n \ nnOscar赢得电影：\ n）;
printf（1980：Ordinary People\\\
）;
printf（1981：Chariots of Fire \ n）;
printf（1982：Ghandi \ n）;
printf（1983：Endearment的条款）;
printf（1984：Amadeus \ n）;
printf（1985：Out of Africa\\\
）;
printf（1986：Platoon \ n）;
printf（1987：The Last Emperor \ n）;
printf（1988：Rain man \ n）;
printf（1989：驾驶Miss Daisy）;
printf（\ n \ nn \ n）;
休息;
}否则if（choice2 == 3）
{
printf（1980年代的美国总统：\ n）;
printf（1980：Jimmy Carter \ n）;
printf（1981-1988：Ronald Reagen \ n）;
printf（1989：George Bush \ n）;
printf（\ n \ nn \ n）;
休息;
}否则if（choice2 == 4）
{
exit（1）;
}其他
{
printf（抱歉，这不是一个有效的选择！\ n）;
休息;
}
}
//这是1990年代的情况。
//与顶层菜单不同，没有数据验证
// do-while循环
case（2）：
{
printf（\ n \ n你想看到什么？\ n）;
printf（1。Baseball \ n）;
printf（2.the movies\）;
printf（3。美国Presidients \ n）;
printf（4.Quit\\\
）;
printf（输入你的选择：）;
scanf（％d，& choice2）;
if（choice2 == 1）
{
printf（\ n \ n世界系列赛冠军）;
printf（1990年代：\ n）;
printf（1990：Cincinatti reds\\\
）;
printf（1991：Minnesota Twins \ n）;
printf（1992：Toronto Blue jays\\\
）;
Printf（1993：Toronto Blue Jays \ n）;
printf（1994：No World Series \ n）;
printf（1995：Atlanta Braves \ n）;
printf（1996：New York Yankees \ n）;
printf（1997：Florida Marlins \ n）;
printf（1998：New York Yankees \ n）;
printf（1999 New York Yankess \ n）;
printf（\ n \ nn \ n）;
休息;
}否则如果（choice2 == 2）
{
printf（\ n \ n，奥斯卡获奖电影）;
printf（1990年代：\ n）;
printf（1990：与狼共舞）;
printf（1991：The Silence of the Lambs \ n）;
printf（1992：Unforgiven \ n）;
printf（1993：Schindlers List \\\
）;
printf（1994：？\ n）;
printf（1995：?? \ n）;
printf（1996：The English Patient \ n）;
printf（1997：Titanic \ n）;
printf（1998：Shakespere in Love\ n）;
printf（1999：American Beauty \ n）;
printf（\ n \ nn \ n）;
休息;
}否则if（choice2 == 3）
{
printf（1990年代的\ n \ nnUS总统：\ n）;
printf（1990-1992：George Bush \ n）;
printf（1993-1999：Bill Clinton \ n）;
printf（\ n \ nn \ n）;
休息;
}否则if（choice2 == 4）
{
exit（1）;
}其他
{
printf（抱歉，这不是一个有效的选择！\ n）;
休息;
}
}
//用户选择2000年
案例的部分（3）：
{
printf（你想看到什么？\ n）;
printf（1。Baseball \ n）;
printf（2.The Movies \ n）;
printf（3.美国总统）;
printf（4.Quit\\\
）;
printf（输入您的选择：）;
scanf（％d，& choice2）;
if（choice2 == 1）
{
printf（\ n \ nnWorld series Champions of）;
printf（The 2000's：\ n）;
printf（2000：New York Yankees \ n）;
printf（2001：Arizona Diamondbacks \ n）;
printf（2002：Anaheim Angels \ n）;
printf（2003：Florida Marlins \ n）;
printf（2004：Boston Red Sox \ n）;
printf（2005：Chicago White Sox）;
printf（2006：St. Louis Cardinals\\\
）;
printf（2007：Boston Red Sox \ n）;
printf（2008：Philadelphia Phillies\\\
）;
printf（2009：New York Yankees \ n）;
printf（\ n \ nn \ n）;
休息;
}否则如果（choice2 == 2）
{
printf（\ n \ nnOscar赢得电影）;
printf（2000年代：\ n）;
printf（2000：Gladiator\\\
）;
printf（2001：A Beautiful Mind \ n）;
printf（2002：Chicago \ n）;
printf（2003：指环王之家）;
printf（2004：Million Dollar Baby \ n）;
printf（2005：Crash \ n）;
printf（2006：The Deeded\\\
）;
printf（2007：没有老人的国家）;
printf（2008：Slumdog Millionaire \ n）;
printf（2009：The Hurt Locker \ n）;
printf（\ n \ nn \ n）;
休息;
}否则if（choice2 == 3）
{
printf（\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n \\ n'中的总统）;
printf（2000：Bill Clinton \ n）;
printf（2001-2008：George W Bush \ n）;
printf（2009：Barack Obama \ n）;
printf（\ n \ nn \ n）;
休息;
}否则if（choice2 == 4）
{
exit（1）;
}其他
{
printf（抱歉，这不是一个有效的选择！\ n）;
休息;
}
}
case（4）：
exit（1）;
默认值：printf（\ n％d不是有效的选择。\ n）;
printf（再试一次。\ n）;
休息;
}
} while（（choice1< 1）||（choice1> 4））;
返回0;
}
我的尝试：
我试过查看程序并且没有明显的事情发生。
解决方案
#include <stdio.h>
#include <stdlib.h> // remember if you plan to use exit(), you need
// this header file
main()
{
// Despite being a long program, you only need two variables:
// one for the first menu and one for the second menu
int choice1;
int choice2;
// The potential decade choices
printf("What do you want to see?\n");
printf("1. The 1980's\n");
printf("2. the 1990's\n");
printf("3. The 2000's\n");
printf("4. Quit\n");
//The top menu choice and the switch statement that makes the
// resulting
//information appear are encased in a do-while loop that
//ensures one
// of the four menu choices are made
do
{
printf("Enter your choice: ");
scanf(" %d", &choice1);
switch (choice1)
{
//In the first case, the user picked the 1980's. Now it
//time to see what specific info they need.
case (1) :
{
printf("\nWhat would you like to see?\n");
printf("1. Baseball\n");
printf("2. The movies\n");
printf("3. US Presidents\n");
printf("4. Quit\n");
printf("Enter your choice: ");
scanf(" %d", &choice2);
if (choice2 ==1)
{
printf("\n\nWorld Series Chapions ");
printf(" of the 1980's:\n");
printf("1980: Philadelphia Phillies\n");
printf("1981: Los Angeles Dodgers\n");
printf("1982: St. Louis Cardinals\n");
printf("1983: Baltimore Orioels\n");
printf("1984: Detroit Tigers\n");
printf("1985: Kansas City Royals\n");
printf("1986: New York Mets\n");
printf("1987: Minnesota Twins\n");
printf("1988: Los Angeles Dodgers\n");
printf(" 1989 Oakland A's\n");
printf("\n\n\n");
break;
} else if (choice2 == 2)
{
printf("\n\nOscar winning movies in the 1980's:\n");
printf("1980: Ordinary People\n");
printf("1981: Chariots of Fire\n");
printf("1982: Ghandi\n");
printf("1983: Terms of Endearment\n");
printf("1984: Amadeus\n");
printf("1985: Out of Africa\n");
printf("1986: Platoon\n");
printf("1987: The Last Emperor\n");
printf("1988: Rain man\n");
printf("1989: Driving Miss Daisy");
printf("\n\n\n");
break;
} else if (choice2 == 3)
{
printf("\n\n US Presidents in the 1980's:\n");
printf("1980: Jimmy Carter\n");
printf(" 1981-1988: Ronald Reagen\n");
printf("1989: George Bush\n");
printf("\n\n\n");
break;
} else if (choice2 == 4)
{
exit(1);
} else
{
printf("Sorry, that is not a valid choice!\n");
break;
}
}
//This is the case for the 1990's.
// Unlike the top menu, there isn't a data validation
//do-while loop
case (2) :
{
printf("\n\n What would you like to see?\n");
printf("1. Baseball\n");
printf("2. The movies\n");
printf("3. US Presidients\n");
printf("4. Quit\n");
printf(" Enter you choice:");
scanf(" %d", &choice2);
if (choice2 ==1)
{
printf("\n\n World Series Champions of");
printf("the 1990's:\n");
printf("1990: Cincinatti reds\n");
printf("1991: Minnesota Twins\n");
printf("1992: Toronto Blue jays\n");
Printf("1993: Toronto Blue Jays\n");
printf("1994: No World Series\n");
printf("1995: Atlanta Braves\n");
printf("1996: New York Yankees\n");
printf("1997: Florida Marlins\n");
printf("1998: New York Yankees\n");
printf("1999 New York Yankess\n");
printf("\n\n\n");
break;
} else if (choice2 == 2)
{
printf("\n\n Oscar winning Movies in ");
printf(" the 1990's:\n");
printf("1990: Dances with Wolves\n");
printf("1991: The Silence of the Lambs\n");
printf("1992: Unforgiven\n");
printf("1993: Schindlers List\n");
printf("1994: ?\n");
printf("1995: ??\n");
printf("1996: The English Patient\n");
printf("1997: Titanic\n");
printf("1998: Shakespere in Love\n");
printf("1999: American Beauty\n");
printf("\n\n\n");
break;
} else if (choice2 == 3)
{
printf("\n\nUS Presidents in the 1990's:\n");
printf("1990-1992: George Bush\n");
printf("1993-1999: Bill Clinton\n");
printf("\n\n\n");
break;
} else if (choice2 == 4)
{
exit (1);
} else
{
printf("Sorry, that is not a valid choice!\n");
break;
}
}
// The section for when the user selects the 2000's
case (3) :
{
printf("\n\nWhat would you like to see?\n");
printf("1. Baseball\n");
printf("2. The Movies\n");
printf("3. US Presidents\n");
printf("4. Quit\n");
printf("Enter your choice:");
scanf(" %d", &choice2);
if (choice2 == 1)
{
printf("\n\nWorld series Champions of ");
printf("The 2000's:\n");
printf("2000: New York Yankees\n");
printf("2001: Arizona Diamondbacks\n");
printf("2002: Anaheim Angels\n");
printf("2003: Florida Marlins\n");
printf("2004: Boston Red Sox\n");
printf("2005: Chicago White Sox");
printf("2006: St. Louis Cardinals\n");
printf("2007: Boston Red Sox\n");
printf("2008: Philadelphia Phillies\n");
printf("2009: New York Yankees\n");
printf("\n\n\n");
break;
} else if (choice2 == 2)
{
printf("\n\nOscar winning movies in ");
printf("the 2000's: \n");
printf("2000: Gladiator\n");
printf("2001: A Beautiful Mind\n");
printf("2002: Chicago\n");
printf("2003: The Lord of the Rings\n");
printf("2004: Million Dollar Baby\n");
printf("2005: Crash\n");
printf("2006: The Departed\n");
printf("2007: No Country for Old Men\n");
printf("2008: Slumdog Millionaire\n");
printf("2009: The Hurt Locker\n");
printf("\n\n\n");
break;
} else if (choice2 == 3)
{
printf("\n\nUS Presidents in the 2000's\n");
printf("2000: Bill Clinton\n");
printf("2001-2008: George W Bush\n");
printf("2009: Barack Obama\n");
printf("\n\n\n");
break;
} else if (choice2 == 4)
{
exit(1);
} else
{
printf("Sorry, that is not a valid choice!\n");
break;
}
}
case (4) :
exit (1);
default : printf("\n%d is not a valid choice.\n");
printf("Try again.\n");
break;
}
} while ((choice1 < 1) || (choice1 > 4));
return 0;
}
What I have tried:
I have tried looking over the program and nothing obvious his coming up.
解决方案
这篇关于我收到一条评论“id返回1退出状态。我做错了什么的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！