本文介绍了dridview没有显示任何数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

SqlConnection objCon = new SqlConnection(@Data Source = MIS-PC; Initial Catalog = projecthotel; Integrated Security = True);



SqlCommand objCmd = new SqlCommand();

objCmd.Connection = objCon;



string query =insert into Reservation values('+ textBox1.Text + ','+ comboBox2.Text +','+ textBox4.Text +','+ textBox6.Text +','+ textBox7.Text +','+ textBox15.Text + ','+ comboBox7.Text +','+ comboBox8.Text +','+ comboBox9.Text +','+ textBox25.Text +','+ textBox17.Text + ','+ textBox18.Text +','+ textBox20.Text +','+ textBox21.Text +');



objCmd.CommandText = query;



objCon.Open();

int j = objCmd.ExecuteNonQuery();

if(j> 0)

{



MessageBox.Show(Record Inserted,www.codingresolved.com);

dataGridView3.Rows.Clear();

}



objCon.Close();



Form1 form1 = new Form1();

form1.Show();

}

SqlConnection objCon = new SqlConnection(@"Data Source=MIS-PC;Initial Catalog=projecthotel;Integrated Security=True");

SqlCommand objCmd = new SqlCommand();
objCmd.Connection = objCon;

string query = "insert into Reservation values('" + textBox1.Text + "', '" + comboBox2.Text + "','" + textBox4.Text + "','" + textBox6.Text + "','" + textBox7.Text + "','" + textBox15.Text + "','" + comboBox7.Text + "','" + comboBox8.Text + "','" + comboBox9.Text + "','" + textBox25.Text + "','" + textBox17.Text + "','" + textBox18.Text + "','" + textBox20.Text + "','" + textBox21.Text + "')";

objCmd.CommandText = query;

objCon.Open();
int j = objCmd.ExecuteNonQuery();
if (j > 0)
{

MessageBox.Show("Record Inserted","www.codingresolved.com");
dataGridView3.Rows.Clear();
}

objCon.Close();

Form1 form1 = new Form1();
form1.Show();
}

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09-23 08:10