本文介绍了TypeError:'RelatedManager'对象不可迭代的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
Django
我有下一个机型:
class Group(models.Model):
name = models.CharField(max_length=100)
parent_group = models.ManyToManyField("self", blank=True)
def __unicode__(self):
return self.name
class Block(models.Model):
name = models.CharField(max_length=100)
app = models.CharField(max_length=100)
group = models.ForeignKey(Group)
def __unicode__(self):
return self.name
说,块 b1 有 g1 组。通过这个名字我想从 g1 组中获取所有块。我写了下面的递归函数:
say, block b1 has g1 group. By it's name I want to get all blocks from group g1. I wrote next recursive function:
def get_blocks(group):
def get_needed_blocks(group):
for block in group.block_set:
blocks.append(block)
if group.parent_group is not None:
get_needed_blocks(group.parent_group)
blocks = []
get_needed_blocks(group)
return blocks
但 b1.group.block_set 返回我 RelatedManager 对象,这是不可迭代的。
but b1.group.block_set returns me RelatedManager object, which is not iterable.
?怎么了?
推荐答案
尝试这样:
block in group.block_set.all()
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