问题描述
我从标题知道,您可能会认为这是重复的,但并非如此.
I know from the title you might think that this is a duplicate but it's not.
for id,row in enumerate(rows):
columns = row.findall("td")
teamName = columns[0].find("a").text, # Lag
playedGames = columns[1].text, # S
wins = columns[2].text,
draw = columns[3].text,
lost = columns[4].text,
dif = columns[6].text, # GM-IM
points = columns[7].text, # P - last column
dict[divisionName].update({id :{"teamName":teamName, "playedGames":playedGames, "wins":wins, "draw":draw, "lost":lost, "dif":dif, "points":points }})
这是我的Python代码的样子.大部分代码已删除,但本质上我是从网站中提取一些信息.我将信息保存为字典.当我打印字典时,每个值周围都有一个括号["blbal"],这会在我的Iphone应用程序中引起麻烦.我知道我可以将变量转换为字符串,但是我想知道是否有一种方法可以直接将信息作为字符串获取.
This is how my Python code looks like. Most of the code is removed but essentially i am extracting some information from a website. And i am saving the information as a dictionary. When i print the dictionary every value has a bracket around them ["blbal"] which causes trouble in my Iphone application. I know that i can convert the variables to strings but i want to know if there is a way to get the information DIRECTLY as a string.
推荐答案
列表中似乎有一个字符串:
That looks like you have a string inside a list:
["blbal"]
要获取字符串,只需索引l = ["blbal"]
print(l[0]) -> "blbal"
.
To get the string just index l = ["blbal"]
print(l[0]) -> "blbal"
.
如果是字符串,请使用str.strip
'["blbal"]'.strip("[]")
或切片'["blbal"]'[1:-1]
(如果它们始终存在).
If it is a string use str.strip
'["blbal"]'.strip("[]")
or slicing '["blbal"]'[1:-1]
if they are always present.
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