获取向量元素的输出有问题吗？

本文介绍了获取向量元素的输出有问题吗？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 我今天正在使用矢量和课程。我尝试做一些不同的事情，在某种程度上我成功了但是我有这个问题得到最终输出。这就是我所做的 - 我创建了一个类水果然后我创建了一个水果矢量（数据类型）并开始在其中推送不同类型的水果对象。它起作用，完全没有问题。但是，当我想获得向量（水果）中的元素的输出时，我只是无法使用正常方式我得到向量元素输出并且它一直给我错误。这是我的代码 - 请有人建议我在哪里犯了错误 - **我没有在这里包含我的水果类代码 #include < iostream > #include < vector > #include fruit.h 使用 命名空间标准; int main（） { fruit apple; // 这是我的水果对象苹果的水果类 fruit cherry; vector< fruit>水果; thefruit.push_back（apple）; thefruit.push_back（cherry）; for （ int i = 0 ; i< thefruit.size（）; i ++） { cout<< 水果向量中的水果是：<< thefruit [i]<< endl; // 这就是我//得到错误的地方 - 错误是no operator<<匹配这个操作数// } system（ pause）; } 解决方案 我认为这比我更好地解释和回答你的问题 http://stackoverflow.com/questions/16513046/error- no-operator-matches-these-operands [ ^ ] 'g' 既然你没有编写fruits类的代码，我们就无法100％肯定。但是这个错误很好地解释了这个问题。 如果你不重载<< 班级内的操作员。 与平等，比较和其他操作员相同。 如果您尝试这样做： if （thefruit [ 1 ] == thefruit [ 2 ]） { // 无论 } 它将抛出相同的错误，但是没有运算符==而是 查看以下链接： http：// www .tutorialspoint.com / cplusplus / cpp_overloading.htm [ ^ ] http://en.cppreference.com/w/ cpp / language / operators [ ^ ] I was working with vectors and classes today. I tried to do something different and to some extent i was successful but then i have this problem getting the final output. This is what i did- I created a class fruit and then i created a vector of fruit(data-type) and started pushing different types of fruit objects in it. It worked and there was no problem at all. But when i wanted to get the output of the elements in the vector (fruits), i just couldn't use the normal way i get the vector elements output and it kept giving me error. This is my code- Please can someone suggest me where i made the mistake- **I haven't include my fruit class code here#include <iostream>#include <vector>#include "fruit.h"using namespace std;int main(){ fruit apple; // this is my fruit class with my fruit object applefruit cherry; vector<fruit> thefruit; thefruit.push_back(apple);thefruit.push_back(cherry);for(int i=0; i<thefruit.size(); i++){ cout<<"The fruits in the fruit vector are:"<<thefruit[i]<<endl;//this is where i //get the error- The error is" no operator "<<" matches this operands//}system("pause");} 解决方案 I think this explains and answers your question better than I could http://stackoverflow.com/questions/16513046/error-no-operator-matches-these-operands[^]'g'Since you didn't wrote the code of the "fruits" class, we can not be 100% sure. But the error is quite explaining the problem.You can not print out a class if you don't overload the << operator within the class.It is the same as with equality, comparison and other operators.If you try to do:if (thefruit[1] == thefruit[2]){ // whatever}It is going to throw the same error but with no operator "==" instead[edit]Have a look to following links:http://www.tutorialspoint.com/cplusplus/cpp_overloading.htm[^]http://en.cppreference.com/w/cpp/language/operators[^] 这篇关于获取向量元素的输出有问题吗？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！