前卫管道运营商的怀疑 | 前卫管道运营商的怀疑

本文介绍了前卫管道运营商的怀疑的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

 来自本课:
 让stockData =
    [
      "2012-03-30,32.40,32.41,32.04,32.26,31749400,32.26"；
      "2012-03-29,32.06,32.19,31.81,32.12,37038500,32.12"；
.....................................................
      "2012-03-01,31.93,32.39,31.85,32.29,77344100,32.29"；
      "2012-02-29,31.89,32.00,31.61,31.74,59323600,31.74"； ]

让splitCommas(x:string)=
    x.Split([|'，'|])

stockData
|> List.map splitCommas
|> List.maxBy(fun x-> abs(float x.[1]-float x.[4]))
|> (有趣的x-> x.[0])
 为什么我不能使用下面的代码? 
   
  (有趣x-> x.[0])(    List.maxBy(有趣x-> abs(float x.[1]-float x.[4]))   
   List.map splitCommas stockData)

解决方案

from the lesson:
let stockData =
    [ 
      "2012-03-30,32.40,32.41,32.04,32.26,31749400,32.26";
      "2012-03-29,32.06,32.19,31.81,32.12,37038500,32.12";
............................................
      "2012-03-01,31.93,32.39,31.85,32.29,77344100,32.29";
      "2012-02-29,31.89,32.00,31.61,31.74,59323600,31.74"; ]

let splitCommas (x:string) =
    x.Split([|','|])

stockData
|> List.map splitCommas
|> List.maxBy (fun x -> abs(float x.[1] - float x.[4]))
|> (fun x -> x.[0])
Why I can not use the code below instead? and How can i code without pipe?
(fun x -> x.[0])(List.maxBy (fun x -> abs(float x.[1] - float x.[4]))
	List.map splitCommas stockData)

解决方案

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