本文介绍了如何编写一个Prolog代码，接受来自用户的CGPA输入并确定该CGPA的级别的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
Write a Prolog code
that accepts input of CGPA from user and determines the level
of that CGPA; > 0 and <
2.00 as "poor", >= 2.00 and < 3.00 as "good" and >= 3.00 as
"excellent". The example of
output for the Prolog code is as follows:
?- run.
Enter your CGPA: 1.60.
Your CGPA is poor.
?- run.
Enter your CGPA: 2.00.
Your CGPA is good.
?- run.
Enter your CGPA: 3.80.
Your CGPA is
excellent.推荐答案
CGPA; > 0 and <
2.00 as "poor", >= 2.00 and < 3.00 as "good" and >= 3.00 as
"excellent". The example of
output for the Prolog code is as follows:
?- run.
Enter your CGPA: 1.60.
Your CGPA is poor.
?- run.
Enter your CGPA: 2.00.
Your CGPA is good.
?- run.
Enter your CGPA: 3.80.
Your CGPA is
excellent.
这篇关于如何编写一个Prolog代码，接受来自用户的CGPA输入并确定该CGPA的级别的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！