问题描述
我正在尝试在Spring MVC中设置OpenSessionInViewInterceptor以修复:org.hibernate.LazyInitializationException:无法初始化代理-没有会话.
I'm trying to set up OpenSessionInViewInterceptor in spring mvc to fix: org.hibernate.LazyInitializationException: could not initialize proxy - no Session.
下面是我已经拥有的代码以及错误的来源.
Below is the code I already have and where the error comes from.
AppConfig.java
AppConfig.java
@Configuration
@PropertySource("classpath:db.properties")
@EnableTransactionManagement
@ComponentScans(value = { @ComponentScan("com.debugger.spring.web.tests"), @ComponentScan("com.debugger.spring.web.service"), @ComponentScan("com.debugger.spring.web.dao"),
@ComponentScan("com.debugger.spring.web.controllers") })
public class AppConfig implements WebMvcConfigurer {
@Autowired
private Environment env;
@Bean
public LocalSessionFactoryBean getSessionFactory() {
LocalSessionFactoryBean factoryBean = new LocalSessionFactoryBean();
Properties props = new Properties();
// Setting JDBC properties
...
// Setting Hibernate properties
...
// Setting C3P0 properties
...
return factoryBean;
}
@Bean
public OpenSessionInViewInterceptor openSessionInViewInterceptor() {
OpenSessionInViewInterceptor openSessionInViewInterceptor = new OpenSessionInViewInterceptor();
openSessionInViewInterceptor.setSessionFactory(getSessionFactory().getObject());
return openSessionInViewInterceptor;
}
}
featured.jsp
featured.jsp
<c:choose>
<c:when
test='${article.user.isSubscribed() and article.user.subscription.type eq "silver" }'>
<a class="bold"
href='${pageContext.request.contextPath}/u/${article.user.username}'><span
class="silvername"> <c:out value="${article.user.name}"></c:out></span></a>
</c:when>
<c:when
test='${article.user.isSubscribed() and article.user.subscription.type eq "gold" }'>
<a class="bold"
href='${pageContext.request.contextPath}/u/${article.user.username}'><span
class="goldname"> <c:out value="${article.user.name}"></c:out></span></a>
</c:when>
<c:when
test='${article.user.isSubscribed() and article.user.subscription.type eq "premium" }'>
<a class="bold"
href='${pageContext.request.contextPath}/u/${article.user.username}'><span
class="premiumname"> <c:out
value="${article.user.name}"></c:out></span></a>
</c:when>
<c:otherwise>
<a class="bold"
href='${pageContext.request.contextPath}/u/${article.user.username}'><span>
<c:out value="${article.user.name}"></c:out>
</span></a>
</c:otherwise>
</c:choose>
$ {article.user.isSubscribed()}最有可能引发错误,因为无法获取用户.我希望它可以不使用急切的获取程序来运行,并且我认为可以通过正确设置OpenSessionInViewInterceptor来实现它.
${article.user.isSubscribed()} throws the error most likely because user cannot be fetched. I want it to run without using eager fetch and I think I can acheive it by setting up OpenSessionInViewInterceptor correctly.
推荐答案
覆盖 WebMvcConfigurer#addInterceptors(InterceptorRegistry)在配置类中:
@Override
public void addInterceptors(InterceptorRegistry registry) {
OpenSessionInViewInterceptor openSessionInViewInterceptor = new OpenSessionInViewInterceptor();
openSessionInViewInterceptor.setSessionFactory(getSessionFactory().getObject());
registry.addWebRequestInterceptor(openSessionInViewInterceptor).addPathPatterns("/**");
}
还要在配置类上添加@EnableWebMvc
.
针对OP的评论:
我不确定为什么它不起作用.对我来说,一切似乎都很好.还有另一种方法可以实现:
I am not sure why it is not working. Everything seems fine to me. There is another way you can achieve this:
设置hibernate.enable_lazy_load_no_trans
属性true
.
请参见 23.9 .1.有关更多信息,请参见《 Hibernate用户指南》中的获取属性" .
但这不是 指南中所述的一个很好的选择:
But this is not a very good option as stated in the guide:
In reality, you shouldn’t probably enable this setting anyway.
这篇关于如何使OpenSessionInViewInterceptor在Spring MVC中工作的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!