本文介绍了通用类和放大器Type.GetType（）的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
一个益智游戏，我有一个泛型类
Bit of a puzzler, I have a generic class
public abstract class MyClass<T> : UserControl
{
}
我有一个类型是这样的
Type type = Type.GetType("Type From DB as String", true, true);
我想用类型创建MyClass的实例...但这不起作用。
and I want to create and instance of MyClass using the type... But this doesn't work.
MyClass<type> control = (MyClass<type>)LoadControl("/UsercControl.ascx");
任何想法????
推荐答案
类似于这样的内容：
Something like this:
Type typeArgument = Type.GetType("Type From DB as String", true, true);
Type template = typeof(MyClass<>);
Type genericType = template.MakeGenericType(typeArgument);
object instance = Activator.CreateInstance(genericType);
现在您无法将 用作 MyClass< T> ，因为你不知道 T ...但你可以用一些不需要 T 的方法定义一个非泛型的基类或接口，然后转换为该类型。或者你可以通过反射来调用它的方法。
Now you won't be able to use that as a MyClass<T> in terms of calling methods on it, because you don't know the T... but you could define a non-generic base class or interface with some methods in which don't require T, and cast to that. Or you could call the methods on it via reflection.
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