本文介绍了如何使用rownumber?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我将从这个字符串中获得一个@ json1
I will get one out put from this string @json1
{
"Status": "Success",
"Status Message": "Service Call Successful",
"Area":
[
{
"AreaCode":"A00009",
"AreaName":"BARSHI",
"FsCode":"TSM010",
"RegionCode":"R00001",
"RegionName":"MAHARASHTRA"
},
{
"AreaCode":"A00008",
"AreaName":"BANGALORE",
"FsCode":"TSM040",
"RegionCode":"R00901",
"RegionName":"KARNATAKA"
},
]
}
现在我想要替换'}'之间的最后一个字符''' d']'符号任何解决方案都将不胜感激..
我尝试过:
i已经尝试了
now i want to replace last charecter ',' between '}' and ']' symbol any solution would be greatly appreciated..
What I have tried:
i have tried
set @json1=reverse(STUFF(REVERSE(@json1),charindex(',',@json1),1,''))
但没有用..
i希望像这样出来
but no use..
i want out put like this
{
"Status": "Success",
"Status Message": "Service Call Successful",
"Area":
[
{
"AreaCode":"A00009",
"AreaName":"BARSHI",
"FsCode":"TSM010",
"RegionCode":"R00001",
"RegionName":"MAHARASHTRA"
},
{
"AreaCode":"A00008",
"AreaName":"BANGALORE",
"FsCode":"TSM040",
"RegionCode":"R00901",
"RegionName":"KARNATAKA"
}
]
}
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