本文介绍了带sqlite的Ionic3-选择的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我在使用Android中的cordova从SQL Lite DB查询记录时遇到了问题
I have issue with querying the records from SQL Lite DB using cordova in Android
this.platform.ready().then(() => {
this.sqlite.create({
name: 'temp.db',
location: 'default'
}).then((db: SQLiteObject) => {
console.log('Querying for temp user '+user.userName+'Password '+user.password);
console.log('User queried'+user.userName);
db.executeSql("SELECT * FROM USER where USER_NAME = ? and USER_PWD=?", [user.userName,password]).then(
response => {
let records='';
for (let i = 0; i < response.rows.length; i++) {
records = records+ JSON.stringify(response.rows.item(i))+'\n'; //Prints row correctly
}
this._util.presentAlert('Records selected like from- USR-',records);
})
.catch(
e => this._util.presentAlert('Fail- Select like from- USER-Temp DBUSER',e));
db.executeSql("SELECT * FROM USER where USER_NAME = ? and USER_PWD=? ", [user.userName,password ]).then(
response => {
if (response && response.rows && response.rows.length > 0) {
for (let i = 0; i < response.rows.length; i++) {
let access = {
firstName :response.rows.item[i].FIRST_NAME, //This is undefined.
lastName :response.rows.item[i].LAST_NAME,
userName:response.rows.item[i].USER_NAME,
userId:response.rows.item[i].USER_ID
}
observer.next(access);
}
observer.complete();
} else {
let access = {status:'Fail',msg:'Bad credentials for Temp DB login'};
console.log('No record for the user from- USER'+user.userName);
observer.next(access);
observer.complete();
}
})
.catch(
e => {
console.log('Fail- Select query gone wrong * from- USER FOR Temp DB LOGIN' + e);
let access = {status:'Fail',msg:'Bad credentials for Temp DB login'};
observer.next(access);
observer.complete();
});
问题是这是正确打印记录
The issue is this one is printing the records correctly
JSON.stringify(response.rows.item(i))
O/P
{'USER_ID':1,'FIRST_NAME':'Temp','LAST_NAME':'User','USER_NAME':'TEMPUSER','USER_PWD':'TEMPPWD'}
以下引发未定义的错误
firstName :response.rows.item[i].FIRST_NAME
Fail- Select query gone wrong * from- USER FOR Temp DB LOGIN TypeError: Cannot read property 'FIRST_NAME' of undefined
的属性 FIRST_NAME
为什么我无法以JSON的形式获取它？
Why am I unable to fetch it as as JSON?
推荐答案
我不知道它有多晚了，但是您必须使用：
I don´t know how late it is, but you must use:
response.rows.item(i).FIRST_NAME
（）而不是[]。
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