本文介绍了rawQuery()语法错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想执行使用SQLite在Android的rawQuery()下面的SQL查询。结果
但我得到结果
         android.database.sqlite.SQLiteException:近状态:语法错误:,在编译:选择emp_id,日期,结束日期fromleave_plans1where状态=?

I want to execute the following SQL query using SQLite's rawQuery() in Android.
But I am getting
"android.database.sqlite.SQLiteException: near "status": syntax error: , while compiling: select emp_id,start_date,end_date fromleave_plans1where status = ?"

SQL查询:选择emp_id,起始日期,从leave_plans END_DATE,其中状态=批准或状态=待定

SQL query : select emp_id,start_date,end_date from leave_plans where status="approved" or status="pending"

和rawQuery我已经使用:

and rawQuery i have used :

db.rawQuery("select emp_id,start_date,end_date from" + TABLE_NAME + "where status = ?",new String[] {"approved","pending"});  

请帮忙

由于结果
sneha

Thanks
sneha

推荐答案

试试这个code:

String[] columns = { "emp_id", "start_date", "end_date" };
String[] whereArguments = { "approved", "pending" };
Cursor cursor = db.query(TABLE_NAME, columns, "status = ? OR status = ?", whereArguments, null, null, null);

这两个问号是在查询的第三个参数必要调用每个字符引用一个元素在 whereArguments 阵列。因此,这个调用将转化为:

The two question marks are necessary in the third argument in the query call as each ? character references one element in the whereArguments array. So this call will translate to:

选择emp_id,日期,结束日期从{} TABLE_NAME WHERE状态=批准或状态=待定;

SELECT emp_id, start_date, end_date FROM {TABLE_NAME} WHERE status = "approved" OR status = "pending";

(通过任何字符串常量它重新presents其中{} TABLE_NAME显然将取代)。

(Where {TABLE_NAME} will obviously be replace by whatever String constant it represents.)

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10-24 14:39