斐波那契计算

问题描述

该程序应该从用户那里获得一个斐波那契数，并且程序将在确定用户输入正数和不小于70的斐波那契数的同时计算该数字.因此，如果用户输入7，它应该打印13.应该使用fibcalc()方法进行计算.尝试编译程序时，出现错误无法将Fibonacci类中的fibcalc方法应用于给定类型: System.out.printf("Fibonacci#％d为％f"，num，fibcalc(num，x3)); 和找不到符号" 返回x3; 这是我的代码:

This program is supposed to get a Fibonacci number from the user and the program will calculate what it is while making sure that the user entered a positive number and a number no less than the Fibonacci number 70. So, if the user entered 7, it should print 13. The method fibcalc() is supposed to do the calculations. When I try and compile the program, I get the errors "method fibcalc in class Fibonacci cannot be applied to given types: System.out.printf("Fibonacci #%d is %f", num, fibcalc(num, x3)); and "cannot find symbol" return x3;Here's my code:

import java.util.Scanner;

public class Fibonacci
{
    public static void main ( String args[] ) 
    {
    Scanner input = new Scanner ( System.in );

        int num; 
        double x3 = 0;


           System.out.print("Which Fibonacci number would you like? ");
       num = input.nextInt(); 
           do
       {
        System.out.print("Which Fibonacci number would you like? ");
        num = input.nextInt(); 
    }while(num >= 0 && num <= 70);

    System.out.printf("Fibonacci #%d is %f", num, fibcalc(num, x3));

}


public static double fibcalc(int num) 
{
    int x1 = 0;
    int x2 = 1;

        if (num == 0)

            return 0;

        else if (num == 1)

            return 1;

        else

            for (int x3 = 0; x3 < num; x3++)
                {
                    x3 = x1 + x2;
                    x1 = x2;
                    x2 = x3;
                }
                return x3;

}
  }

我可能还错过了其他问题.我是Java的新手.预先感谢.

There are probably other problems I've missed. I'm pretty new to java. Thanks in advance.

推荐答案

fibcalc()方法只有一个 int 参数，但是您可以使用两个参数.

The fibcalc() method has a single int parameter, but you are calling it with two parameters.

更改呼叫来源

fibcalc(num, x3)

到

fibcalc(num)

即将该行更改为:

System.out.printf("Fibonacci #%d is %f", num, fibcalc(num));

---

此外，如果您想要准确的结果数字，请从使用 double 更改为使用 BigInteger ，它可以准确地处理任意大数.

---

Also, if you want accurate numbers for your results, change from using double to using BigInteger, which can handle arbitrarily large numbers accurately.

这篇关于斐波那契计算的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！