获取MalformedChunkCodingException而读JSON数据

问题描述

我已经收到此异常在解析JSON数据：

org.apache.http.MalformedChunkCodingException：分块流意外结束

在org.apache.http.impl.io.ChunkedInputStream.getChunkSize

任何人可以建议我该怎么办......我读数据流为：

  HttpPost请求=新HttpPost（URL）;
                StringBuilder的SB =新的StringBuilder（）;
                request.getParams（）的setParameter（CoreProtocolPNames.USE_EXPECT_CONTINUE，Boolean.FALSE）。
                request.setHeader（接受，应用/ JSON）;
                HTT presponse响应= NULL;
                DefaultHttpClient的HttpClient =新DefaultHttpClient（）;
                // DefaultHttpClient的HttpClient = getNewHttpClient（）;
                HttpConnectionParams.setSoTimeout（httpClient.getParams（），超时）;
                HttpConnectionParams.setConnectionTimeout（httpClient.getParams（），超时）;
                响应= httpClient.execute（要求）;
                。InputStream的时间= response.getEntity（）的getContent（）;
                的BufferedReader读卡器=新的BufferedReader（新的InputStreamReader（在））;
                串线= NULL;
                而（（行= reader.readLine（））！= NULL）{
                    sb.append（线）;
                }
                resultString = sb.toString（）;
 

解决方案

我发现解决此方法

 公共静态字符串getResponseStringFromURL（字符串URL，INT超时）
{
        StringBuilder的结果=新的StringBuilder（）;
        DefaultHttpClient的HttpClient =新DefaultHttpClient（）;
        HttpPost请求=新HttpPost（URL）;
        HTT presponse响应= NULL;

        尝试 {
            响应= httpClient.execute（要求）;
        }赶上（ClientProtocolException E）{
            e.printStackTrace（）;
        }赶上（IOException异常E）{
            e.printStackTrace（）;
        }


        HttpEntity实体= response.getEntity（）;
        输入的InputStream = NULL;
        尝试 {
            输入=新的BufferedInputStream（response.getEntity（）的getContent（））;
        }赶上（IllegalStateException异常E）{
            // TODO自动生成的catch块
            e.printStackTrace（）;
        }赶上（IOException异常E）{
            // TODO自动生成的catch块
            e.printStackTrace（）;
        }
        字节的数据[] =新的字节[40000]

        长totalContactsCount = -1;
        INT readContactsCount = 0;
        INT currentByteReadCount = 0;

        / **从inpus流*读取应答/
        尝试 {
            而（（currentByteReadCount = input.read（数据））！=  -  1）{
                字符串READDATA =新的String（数据，0，currentByteReadCount）;
                result.append（READDATA）;

                //每然后+1进步...}，{...（JSON对象分离器）
                如果（readData.indexOf（}〜{）＆GT; = 0）{
                    readContactsCount ++;
                }

               / * //发布进度....
                如果（totalContactsCount大于0）{
                    publishProgress（（int）的（readContactsCount * 100 / totalContactsCount））;
                } * /
            }
        }赶上（IOException异常E）{
            // TODO自动生成的catch块
            e.printStackTrace（）;
        }
        尝试 {
            input.close（）;
        }赶上（IOException异常E）{
            // TODO自动生成的catch块
            e.printStackTrace（）;
        }

        / **变换反应到JSONArray * /
        返回result.toString（）;

    }
 

I have getting this exception while parsing JSON data :

org.apache.http.MalformedChunkCodingException: Chunked stream ended unexpectedly

at org.apache.http.impl.io.ChunkedInputStream.getChunkSize

can any one suggest me what to do ...I am reading stream As :

HttpPost request = new HttpPost(url);
                StringBuilder sb=new StringBuilder();
                request.getParams().setParameter(CoreProtocolPNames.USE_EXPECT_CONTINUE, Boolean.FALSE);
                request.setHeader("Accept", "application/json");
                HttpResponse response =null;
                DefaultHttpClient httpClient = new DefaultHttpClient();
                //DefaultHttpClient httpClient = getNewHttpClient();
                HttpConnectionParams.setSoTimeout(httpClient.getParams(), timeOut); 
                HttpConnectionParams.setConnectionTimeout(httpClient.getParams(),timeOut); 
                response = httpClient.execute(request); 
                InputStream in = response.getEntity().getContent();
                BufferedReader reader = new BufferedReader(new InputStreamReader(in));
                String line = null;
                while((line = reader.readLine()) != null){
                    sb.append(line);
                }
                resultString = sb.toString();

解决方案

I found Solution From this method

public static String getResponseStringFromURL(String url,int timeOut)
{ 
        StringBuilder  result = new StringBuilder();
        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost request = new HttpPost(url);
        HttpResponse response =null;

        try {
            response = httpClient.execute(request);
        } catch (ClientProtocolException e) {   
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }


        HttpEntity entity = response.getEntity();
        InputStream input = null;
        try {
            input = new BufferedInputStream(response.getEntity().getContent());
        } catch (IllegalStateException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        byte data[] = new byte[40000];

        long totalContactsCount = -1;
        int readContactsCount = 0;
        int currentByteReadCount = 0;

        /** read response from inpus stream */
        try {
            while ((currentByteReadCount = input.read(data)) != -1) {
                String readData = new String(data, 0, currentByteReadCount);
                result.append(readData);

                // then +1 progress on every ...},{... (JSON object separator)
                if (readData.indexOf("}~{") >= 0) {
                    readContactsCount++;
                }

               /* // publishing the progress....
                if (totalContactsCount > 0) {
                    publishProgress((int)(readContactsCount * 100 / totalContactsCount));
                }*/
            }
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        try {
            input.close();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        /** transform response into JSONArray */
        return result.toString();

    }

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