使用bash打印数组中最大值的索引

问题描述

我正在尝试在数组中打印最大值的索引值.我写了这样的东西:

I am trying to print index value of maximum value in an array. I wrote something like this:

my_array=( $(cat /etc/grub.conf | grep title | cut -d " " -f 5,7 | tr -d '()'|cut -c1-6) )
echo "${my_array[*]}" | sort -nr | head -n1
max=${my_array[0]}
for v in ${my_array[@]}; do
    if (( $v > $max )); then max=$v; fi;
done
echo $max

此脚本的输出如下:

4.9.85 4.9.38
./grub_update.sh: line 6: ((: 4.9.85 > 0 : syntax error: invalid arithmetic operator (error token is ".9.85 > 0 ")
./grub_update.sh: line 6: ((: 4.9.38 > 0 : syntax error: invalid arithmetic operator (error token is ".9.38 > 0 ")
0

要求:我想查询grub.conf并读取Kenrnel行，然后在数组中打印最新内核的索引值

Requirement: I want to query grub.conf and read Kenrnel line followed by printing index value of latest kernel in the array

kernel /boot/vmlinuz-4.9.38-16.35.amzn1.x86_64 root=LABEL=/ console=tty1 console=ttyS0 selinux=0

推荐答案

• 如果数字对齐，则可以进行字符串比较.
• printf 可以对齐数字
• You can do string comparisons if the digits are aligned.
• printf can align the digits

data=(
    4.9.85
    4.9.38
    3.100.20.2
    4.12.2.4.5
    4.18.3
)

findmax(){
    local cur
    local best=''
    local ans

    for v in "$@"; do
        cur="$(
            # split on dots
            IFS=.
            printf '%04s%04s%04s%04s%04s' $v
        )"
        # note: sort order is locale-dependent
        if [[ $cur > $best ]]; then
            ans="$v"
            best="$cur"
        fi
    done
    echo "$ans"
}

echo "max = $(findmax "${data[@]}")"

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