本文介绍了如何将图像上传到服务器的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想模仿这个请求
I want emulate this request
-----------------------------708299735697
Content-Disposition: form-data; name="_file"
1.jpg
-----------------------------708299735697
Content-Disposition: form-data; name="file"; filename="blob"
Content-Type: image/png
‰PNG
............
var taimalda = DateTime.Now.Ticks;
var boundary = "------------------------" + taimalda ;
var newLine = Environment.NewLine;
var propFormat = "--" + boundary + newLine +
"Content-Disposition: form-data; name=\"{0}\"" + newLine + newLine +
"{1}" + newLine;
var fileHeaderFormat = "--" + boundary + newLine +
"Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"" + newLine + "Content-Type: image/png";
var req = (HttpWebRequest)HttpWebRequest.Create("http://xxx.ru/new_style/flash_uploader/upload.php?fileapi"+taimalda);
req.CookieContainer = s;
System.Net.ServicePointManager.Expect100Continue = false;
req.Referer = "http://www.xxx.ru/user/setting/set_info";
req.UserAgent = "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:2.0) Gecko/20100101 Firefox/4.0";
req.Method = WebRequestMethods.Http.Post;
req.ContentType = "multipart/form-data; boundary=" + boundary;
using (var reqStream = req.GetRequestStream())
{
var reqWriter = new StreamWriter(reqStream);
var tmp = string.Format(propFormat, "_file", "1.jpg");
reqWriter.Write(tmp);
tmp = string.Format(fileHeaderFormat, "file", "blob");
reqWriter.Write(tmp);
reqWriter.Flush();
}
var res = req.GetResponse();
using (var resStream = res.GetResponseStream())
{
var reader = new StreamReader(resStream);
var ext = reader.ReadToEnd();
}
但这段代码只发送了没有我文件的标题(1.jpg)
but this code sent only headers without my file(1.jpg)
--------------------------635031060420469298
Content-Disposition: form-data; name="_file"
1.jpg
--------------------------635031060420469298
Content-Disposition: form-data; name="file"; filename="blob"
Content-Type: image/png
推荐答案
FileStream fs = new FileStream("1.jpg", FileMode.Open, FileAccess.Read);
int bufferSize = 40960; //Amount of data that to be read from file(in bytes)
byte[] buffer = br.ReadBytes(bufferSize);//reading the bytes
......
req.ContentType = "multipart/form-data; boundary=" + boundary;
using (var reqStream = req.GetRequestStream())
{
var reqWriter = new StreamWriter(reqStream);
var tmp = string.Format(propFormat, "_file", "1.jpg");
reqWriter.Write(tmp);
tmp = string.Format(fileHeaderFormat, "file", "blob");
reqWriter.Write(tmp);
int ken = fs.Read(buffer, 0, buffer.Length);
reqWriter.Write(buffer,0,ken); // cannot convert byte[] to char[]
reqWriter.Flush();
}
private byte[] GetBytes(string str)
{
byte[] bytes = new byte[str.Length * sizeof(char)];
System.Buffer.BlockCopy(str.ToCharArray(), 0, bytes, 0, bytes.Length);
return bytes;
}
稍微修改你的流代码:
Modify your stream code a bit:
FileStream fs = new FileStream("1.jpg", FileMode.Open, FileAccess.Read);
req.ContentType = "multipart/form-data; boundary=" + boundary;
using (var stream = req.GetRequestStream())
{
var tmp = string.Format(propFormat, "_file", "1.jpg");
stream.Write(GetBytes(tmp));
tmp = string.Format(fileHeaderFormat, "file", "blob");
stream.Write(GetBytes(tmp));
stream.Flush();
fs.CopyTo(stream);
stream.Flush.Flush();
}
You need to convert string to bytes in order to be able to write to a Stream. You will need to discard StreamWriter as it won't allow to write bytes to a stream.
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