如何从PHP中的JSON数组中删除对象

问题描述

我有一个JSON数组.我想删除编号为 4 的条目，并返回剩余的数组

I have a JSON array. I want to delete the entry that have number 4 and return the left over array

$filters = '{"1":1,"2":2,"3":4}';
$fobj = json_decode($filters, TRUE);

foreach($fobj as $key => $value) 
{ 
if (in_array(4, $fobj)) {
 unset($fobj[4]);
  }
}
echo $filters = json_encode($fobj );

但是这个 echo 并没有给我我想要的东西.我希望它返回如下内容:

But this echo does not give me what I want. I want it to return something like this:

  {"1":1,"2":2}

推荐答案

您要删除数组的第四个值，而不是该值.改用 array_search

You're removing the fourth value of the array, not the value. Use array_search instead

$filters = '{"1":1,"2":2,"3":4}';
$fobj = json_decode($filters, TRUE);
$search = array_search(4, $fobj);
if($search !== false) unset($fobj[$search]);
echo $filters = json_encode($fobj );

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