序言:介于/3之间，末尾有一个列表

是否可以在/3和第三个参数之间建立一个列表，所以如果您问between(2,6,X).它来了X=[2,3,4,5,6]不喜欢X=2X=3X=4....我不知道该如何工作(我的所有解决方案均无效.)我是Prolog的初学者，所以我不知道.对不起，英语不好.感谢您的帮助:)解决方案首先进入图书馆并获得一本好书，例如Sterling和Shapiro的序言的艺术".两种方式:?- findall(X, between(2, 6, X), Xs).Xs = [2, 3, 4, 5, 6].您还应该查看bagof/3和setof/3.对于直接方法numlist/3，请参见例如 SWI-Prolog的实现.没有参数检查，它可以归结为:numlist(U, U, List) :- !, List = [U].numlist(L, U, [L|Ns]) :- L2 is L+1, numlist(L2, U, Ns).有几种方法可以打破谓词的原状.?- numlist(1,0,L).不会终止.您需要先检查参数，然后再将其传递给此特定版本的numlist/3:must_be(integer, L),must_be(integer, U),L =< U这些检查并入链接的SWI-Prolog实现的库谓词numlist/3中.my question comes up because of this questionCan you write between/3 in pure prolog?would it be possible to make between/3 and the third argument is a list so if you askbetween(2,6,X).it comesX=[2,3,4,5,6]and not likeX=2X=3X=4....I can’t figure out how this must work (all my solutions don’t work..)I’m a Prolog beginner so I have no idea..sorry for the bad English..Thanks for your help :) 解决方案 Start by going to the library and getting a good book, for example "The Art of Prolog" by Sterling and Shapiro.Two ways:?- findall(X, between(2, 6, X), Xs).Xs = [2, 3, 4, 5, 6].You should also take a look at bagof/3 and setof/3.For a direct way, numlist/3, see for example the SWI-Prolog implementation. Without argument checking it comes down to:numlist(U, U, List) :- !, List = [U].numlist(L, U, [L|Ns]) :- L2 is L+1, numlist(L2, U, Ns).There are several ways to break the predicate as it stands.?- numlist(1,0,L).will not terminate. You need to either check the arguments before passing them to this particular version of numlist/3:must_be(integer, L),must_be(integer, U),L =< UThese checks are incorporated in the library predicate numlist/3 from the linked SWI-Prolog implementation. 这篇关于序言:介于/3之间，末尾有一个列表的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！