如何在Bash中杀死TCP端口16969?

问题描述

我有一个使用TCP端口16969的应用程序.有时它需要快速动态重启软件内核.但是，如果我启动得太快，我就会被锁定

I have an application which uses TCP port 16969. It sometimes requires a quick software kernel reboot on the fly. But if I launch it too fast, I am locked with

所以我想触发我的Bash脚本，该脚本可以使用16969杀死所有正在运行或监听的端口，但是我该怎么做?

So I want to trigger my Bash script which can kill any running or listening port with 16969, but how can I do that?

$ lsof -w -n -i tcp:16969 # this gives me a list of 50 lines but how can I kill them all?

推荐答案

我认为:

lsof -i tcp:22 | grep LISTEN | awk '{print $2}' | xargs kill

应该做到这一点.

要在松散之前仔细检查它想运行什么命令，请在 kill 之前添加 echo ，如下所示:

To double check what commands it wants to run before letting it loose add an echo before the kill like this:

lsof -i tcp:22 | grep LISTEN | awk '{print $2}' | xargs echo kill

然后它将列出通常会杀死的PID

It'll then list the PIDs that it would ordinarily kill

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