本文介绍了Android Picker隐藏上限值和下限值的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
numberPicker1= (NumberPicker) findViewById(R.id.numberPicker1);
final String genders[] = { "red", "blue", "green"};
numberPicker1.setMinValue(0);
numberPicker1.setMaxValue(genders.length - 1);
numberPicker1.setDisplayedValues(genders);
numberPicker1.setDescendantFocusability(NumberPicker.FOCUS_BLOCK_DESCENDANTS);;
NumberPicker.OnValueChangeListener myValChangedListener = new NumberPicker.OnValueChangeListener() {
@Override
public void onValueChange(NumberPicker picker, int oldVal, int newVal) {
Toast.makeText(MainActivity.this,
"Value: " + genders[newVal], Toast.LENGTH_LONG).show();
}
};
显示随机选择器如何隐藏上一个和下一个值/字符串?
it disply random pickerhow to hide previous one and next one value/string?
推荐答案
不幸的是，我发现没有办法这样做...对于那些想要替代解决方案的人.我尝试使用Viewpager而不是数字选择器使它垂直，我尝试链接并应用了Onpagechangelistner.简单地完成...
Unfortunately I find out there is no way to do it so...For them who want alternate solution....I applied Viewpager instead of number picker to make it vertical i tried link and applied Onpagechangelistner.Simply done...
对那些正在为Numbericker寻找解决问题的人表示抱歉！
Sorry for those who are looking for solve issue For Numbericker!!
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