本文介绍了如何在PHP的mysql中只显示一次注释?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述 我有两张桌子:multiple_image和帖子 数据库结构===> multiple_image: | id |图片| imagesid | -------------------------- | 1 |名字| 5557 | | 2 |名字| 5557 | | 3 |名字| 5585 | -------------------------- 帖子: | commentid |评论| iamgesid | ------------------------------------ | 1 |傻瓜| 5557 | | 2 |傻瓜2 5585 | 我想要实现的输出是: 我想要显示所有图像对于具有相同imagesid的评论,但我的问题是,评论正在重复。 我尝试了什么: $ sql =SELECT image,posts.imagesid,multiple_image.imagesid,comment FROM multiple_image JOIN post ON(multiple_image.imagesid = posts.imagesid); $ result = $ conn-> query($ sql); if(!$ result){ trigger_error('无效查询:'。$ conn->错误); } if($ result-> num_rows> 0){ //每行输出数据 while($ row = $ result-> fetch_assoc()){ echo $ row ['comment']; $ imgs =< div id ='img_div'>< img width =''src ='upload /\".$ row ['image']。'>< / div> ; echo $ imgs; } } 解决方案 sql =SELECT image,posts.imagesid,multiple_image.imagesid,comment FROM multiple_image JOIN帖子ON(multiple_image.imagesid = posts.imagesid); result = conn-> query( I have two tables: multiple_image and postsThe db structures ===>multiple_image:| id | image | imagesid |--------------------------| 1 | name | 5557 || 2 | name | 5557 || 3 | name | 5585 |--------------------------posts:| commentid | comment | iamgesid |------------------------------------| 1 | fool | 5557 || 2 | fool2 | 5585 |The output that I am trying to achieve is:I want to display all the images for a comment which has the same imagesid, but my problem is that, the comment is repeating itself.What I have tried:$sql = "SELECT image, posts.imagesid, multiple_image.imagesid, comment FROM multiple_image JOIN posts ON (multiple_image.imagesid=posts.imagesid)";$result = $conn->query($sql);if (!$result) { trigger_error('Invalid query: ' . $conn->error);}if ($result->num_rows > 0) { // output data of each rowwhile($row = $result->fetch_assoc()) {echo $row['comment'];$imgs= "<div id='img_div'><img width='' src='upload/".$row['image']."' ></div>";echo $imgs;}} 解决方案 sql = "SELECT image, posts.imagesid, multiple_image.imagesid, comment FROM multiple_image JOIN posts ON (multiple_image.imagesid=posts.imagesid)";result =conn->query( 这篇关于如何在PHP的mysql中只显示一次注释?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持! 09-17 22:05