为什么在 Java 中实例化 SimpleEmail 类时会收到此异常?

问题描述

我想做的就是用 Java 发送电子邮件.这是我找到的示例:

All I want to do is send an email in Java. Here is the example I found:

import org.apache.commons.mail.SimpleEmail;

public class Email {

    public static void sendMessage(String emailaddress, String subject, String body) {
        try {
            SimpleEmail email = new SimpleEmail();
            email.setHostName("valid ip address here");
            email.addTo(emailaddress);
            email.setFrom("[email protected]", "No reply");
            email.setSubject(subject);
            email.setMsg(body);
            email.send();
        } catch (Exception ex) {
            ex.printStackTrace();
        }
    }
}

我立即在 SimpleEmail email = new SimpleEmail(); 行收到以下异常:

I immediately get the following exception on the SimpleEmail email = new SimpleEmail(); line:

java.lang.ClassNotFoundException: org.apache.commons.mail.SimpleEmail

我的项目中有以下 JAR(使用 Netbeans):commons-email-1.2.jar

I have the following JAR in my project (using Netbeans):commons-email-1.2.jar

我做错了什么?

谢谢.

推荐答案

不知道为什么 SimpleEmail 不起作用.但这确实做到了:

Not sure why SimpleEmail didn't work. But this did:

import javax.mail.*;
  import javax.mail.internet.*;

  import java.util.Properties;

  public class Email {

     public static void sendMessage(String emailaddress, String subject, String body) {
        try {
           Properties props = new Properties();
           props.setProperty("mail.transport.protocol", "smtp");
           props.setProperty("mail.host", "myhost");

           Session mailSession = Session.getDefaultInstance(props, null);
           Transport transport = mailSession.getTransport();

           MimeMessage message = new MimeMessage(mailSession);
           message.setSubject("Testing javamail plain");
           message.setContent("This is a test", "text/plain");
           message.addRecipient(Message.RecipientType.TO, new InternetAddress("[email protected]"));

           transport.connect();
           transport.sendMessage(message,
                   message.getRecipients(Message.RecipientType.TO));
           transport.close();
        } catch (Exception ex) {
           ex.printStackTrace();
        }
     }
  }

感谢您的建议.

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