问题描述
我正在尝试在python上制作答题器游戏,但我不断收到错误"TypeError: unorderable types: IntVar() > int()"
,我看过其他帖子,但仍然不了解.get
的内容.到目前为止,这是我的代码:
I'm trying to make a clicker game on python but I keep getting the error "TypeError: unorderable types: IntVar() > int()"
I have looked at other posts and still don't understand the .get
thing. here is my code so far:
import tkinter
from tkinter import *
import sys
root = tkinter.Tk()
root.geometry("160x100")
root.title("Cliker game")
global counter
counter = tkinter.IntVar()
global multi
multi = 1
def onClick(event=None):
counter.set(counter.get() + 1*multi)
tkinter.Label(root, textvariable=counter).pack()
tkinter.Button(root, text="I am Cookie! Click meeeeee", command=onClick,
fg="dark green", bg = "white").pack()
clickable = 0
def button1():
global multi
global counter
if counter > 79: # this is the line where the error happens
counter = counter - 80
multi = multi + 1
print ("you now have a multiplier of", multi)
else:
print ("not enough moneys!")
b = Button(text="+1* per click, 80 cookies", command=button1)
b.pack()
root.mainloop()
推荐答案
您必须比较相同的类型(或兼容的类型).在这种情况下,似乎IntVar
对象不能直接与int
比较.但是它有一个get
方法,该方法返回一个整数.
you have to compare identical types (or compatible types). In that case, it seems that the IntVar
object cannot be directly compared to int
. But it has a get
method that returns an integer.
我不是tk
专家,但这重现了问题并提供了解决方法:
I'm not a tk
specialist but this reproduces the issue and provides a fix:
>>> root = tkinter.Tk()
>>> counter = tkinter.IntVar()
>>> counter.get()
0
>>> counter < 10
Traceback (most recent call last):
File "<string>", line 301, in runcode
File "<interactive input>", line 1, in <module>
TypeError: unorderable types: IntVar() < int()
>>> counter.get() < 10
True
>>>
根据您的情况,更改:
if counter > 79:
作者
if counter.get() > 79:
如评论所建议,您在其他地方遇到了这些问题.因此,请使用.get
和.set
,其中整数& IntVar
对象混合在一起.
As comments suggested, you have those issues at other places. So use .get
and .set
where integers & IntVar
objects are mixed.
这篇关于TypeError:不可排序的类型:IntVar()> int()的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!