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问题描述

我目前正在尝试在 C#(最新的 .NET 和 Visual Studio 2008)中拆分一个字符串,以便检索方括号内的所有内容并丢弃剩余的文本.

I'm currently trying to split a string in C# (latest .NET and Visual Studio 2008), in order to retrieve everything that's inside square brackets and discard the remaining text.

例如:H1 受体拮抗剂 [HSA:3269] [PATH:hsa04080(3269)]"

在这种情况下,我有兴趣将HSA:3269"和PATH:hsa04080(3269)"放入一个字符串数组中.

In this case, I'm interested in getting "HSA:3269" and "PATH:hsa04080(3269)" into an array of strings.

如何实现?

推荐答案

Split 在这里帮不了你;你需要使用正则表达式:

Split won't help you here; you need to use regular expressions:

// using System.Text.RegularExpressions;
// pattern = any number of arbitrary characters between square brackets.
var pattern = @"[(.*?)]";
var query = "H1-receptor antagonist [HSA:3269] [PATH:hsa04080(3269)]";
var matches = Regex.Matches(query, pattern);

foreach (Match m in matches) {
    Console.WriteLine(m.Groups[1]);
}

产生你的结果.

这篇关于C# Regex Split - 方括号内的所有内容的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

09-17 18:04