当编译代码防病毒说是病毒并删除它时

问题描述

我尝试用C ++编写代码.此代码仅使文本文件易于加密并保存到新文件中.当我编译这段代码时，防病毒软件说的是病毒/间谍软件Gen:Variant.Kazy.20825.我不知道为什么是病毒.这是我的代码:

Hi i try to make code in c++. This code only makes text file easy encrypted and save into a new file. And when i compile this code antivirus says, it is virus/spyware Gen:Variant.Kazy.20825. I dont know why it is virus. Here is my code:

#include <iostream>
#include <fstream>
#include <string>


using namespace std;

void controlParameters(int argc){  //check if input parameters are ok
    if(argc == 1){
        cout << "Pokud chcete text zasifrovat, spustte program s parametrem: -enc \"Nazev_souboru.txt\"\n";
        cout << "Pokud ho chcete desifrovat, spustte program s parametrem: -dec \"Nazev_souboru.txt\"\n";
    }else if(argc > 3){
        cout << "Moc parametru. Spustte si program bez parametru.\n";
    }else if(argc < 3){
        cout << "Chybi jeden parametr. Spustte si program bez parametru.\n";
    }else{
        cout << "Vsechno vypada zatim dobre\n";
    }
}

void encryption(string &file);  //encrypt text file
void decryption(string &file);  //decrypt text file
bool controlFile(string &file); //check if file can be opened

int main(int argc, char **argv){
    controlParameters(argc);
    string file;
    file = argv[2];
    if(controlFile(file)){

    }else{
        cout << "Soubor nesel nacist." << endl;
        return -1;
    }
    cout << "Ukonceno.\nZmacknete ENTER pro pokracovani..."<<endl;
    cin.get();
    return 0;
}

bool controlFile(string &file){
    ifstream ifs;
    ifs.open(file);
    if(ifs.is_open()){
        ifs.close();
        return true;
    }else{
        ifs.close();        
        return false;
    }
}

void encryption(string &file){
    ifstream ifs;
    ofstream ofs;
    string line;    
    ifs.open(file);
    ofs.open("encrypt.txt");
    if(ifs.is_open()){
        while(!ifs.eof()){
            getline(ifs,line);
            int a = line.length();
            int i = 0;
            while(i < a){               
                ofs << ((char)(line[i]^100));               
            }
            line.clear();
            ofs << "\n";
        }
    }else{
        cout << "Nelze nacist soubor" << endl;
    }
}

void decryption(string &file){
    ifstream ifs;
    ofstream ofs;
    string line;
    ifs.open(file);
    ofs.open("decrypt.txt");
    if(ifs.is_open()){
        while(!ifs.eof()){
            getline(ifs,line);
            int a =line.length();
            int i = 0;
            while(i < a){               
                ofs << ((char)(line[i]^100));               
            }
            line.clear();
            ofs << "\n";
        }
    }else{
        cout << "Nelze nacist soubor" << endl;
    }
}

推荐答案

从病毒扫​​描程序中排除源代码控制目录是一种很好的做法.即使执行源代码控制操作或编译时没有误报，它们也可能导致性能和锁定问题(我已经见过多次).

It's good practice to exclude your source-control directories from virus scanners; they can cause performance and locking problems even if there are no false positives while performing source-control actions or compiling (I've seen it happen several times).

因此，如果只是为了使您的编程体验更可靠，请在这些目录上禁用病毒扫描程序.

So if only to make your programming experience more reliable, disable the virus scanner on those directories.

您可能仍想扫描可执行文件的最终发行版本，以帮助避免误报:毕竟，即使病毒扫描程序不是您的错，也不会给用户留下很好的印象.

You may still want to scan the final, released version of your executable to help avoid false positives: after all, even if it's not your fault the virus scanner chokes, it's not a good impression to leave behind on a user.

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