将石墨指标偏移当前时间范围内的最小值

问题描述

我有Grafana和Graphite指标.我有一个图表，显示ActiveMQ中某些特定队列的EnqueueCount.问题在于EnqueueCount显示自创建队列以来的所有值，因此当我将Grafana中的时间范围缩小到今天到目前为止"时，图形如下所示:

我希望它仅显示当前时间段的值-我希望图形始终从0开始.在这种情况下，我希望将其偏移-2.有一个offset函数，但是它只是按常数，而我需要诸如由时间段内的最小值偏移"之类的东西.

我浏览了石墨文档，但是找不到任何可以请允许我这样做.

有什么想法可以实现这一目标吗?

我们使用的版本:

• Grafana v4.2.0(提交:349f3eb)
• graphite-web-0.9.12-5
• python-carbon-0.9.12-3

解决方案

请使用 nonNegativeDerivative()函数-然后您会获得(在您的指标间隔，通常是)分钟内EnqueueCount变化的 rate .如果您想再次计数-使用 integral() .

所以，integral(nonNegativeDerivative(EnqueueCount))-但是通常人们在寻找利率，那么导数就足够了.

I have Grafana with Graphite metrics. I have a graph showing the EnqueueCount of some specific queue in ActiveMQ. The problem is that the EnqueueCount shows all values since the queue was created, so when I narrow down the time range in Grafana to "today so far", the graph looks like this:

I would like it to show only values for current period - I would like the graph to always start at 0. In this case I would like to offset it by -2. There is an offset function, however it is only by constant, while I would need something like "offset by lowest value in time period".

I went through Graphite documentation, but cannot find any function which would allow me to do this.

Any ideas how I could achieve this?

Versions we use:

• Grafana v4.2.0 (commit: 349f3eb)
• graphite-web-0.9.12-5
• python-carbon-0.9.12-3

解决方案

Please use nonNegativeDerivative() function - then you will get a rate of EnqueueCount change in (your metric interval, usually it is) minute. If you want to get count again - use integral().

So, integral(nonNegativeDerivative(EnqueueCount)) - but usually people looking for rate, then derivative is enough.

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