本文介绍了Swift (iOS 8 SDK) 转换非托管<ABMultiValueRef>到 ABMultiValueRef的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我需要从 AddressBook 框架转换这个函数的返回值:
I need to convert the return value of this function from the AddressBook framework:
ABRecordCopyValue(nil, kABPersonPhoneProperty)
到 ABMultiValueRef 类型的值
to a value of type ABMultiValueRef
此功能目前标记为:
func ABRecordCopyValue(record: ABRecordRef!, property: ABPropertyID) -> Unmanaged<AnyObject>!
所以我可以像这样将其转换为非托管:
So I can convert it to Unmanaged like so:
ABRecordCopyValue(person, kABPersonPhoneProperty) as Unmanaged<ABMultiValueRef>
但是我怎样才能把它作为一个 ABMultiValueRef 来传递给这个函数呢?
But then how can I get it as an ABMultiValueRef so that I can pass it to this function?
func ABMultiValueGetIndexForIdentifier(multiValue: ABMultiValueRef!, identifier: ABMultiValueIdentifier) -> CFIndex
我是这样做的:
let managedPhones = Unmanaged.fromOpaque(phones.toOpaque()).takeUnretainedValue() as ABMultiValueRef
而且我不断收到此编译器错误:
And I keep getting this compiler error:
Bitcast requires both operands to be pointer or neither
%89 = bitcast %objc_object* %88 to %PSs9AnyObject_, !dbg !325
LLVM ERROR: Broken function found, compilation aborted!
Command /Applications/Xcode6-Beta3.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/swift failed with exit code 1
推荐答案
我找到了解决方案:
func peoplePickerNavigationController(
peoplePicker: ABPeoplePickerNavigationController!,
didSelectPerson person: ABRecordRef!) {
/* Do we know which picker this is? */
if peoplePicker != personPicker{
return
}
/* Get all the phone numbers this user has */
let unmanagedPhones = ABRecordCopyValue(person, kABPersonPhoneProperty)
let phones: ABMultiValueRef =
Unmanaged.fromOpaque(unmanagedPhones.toOpaque()).takeUnretainedValue()
as NSObject as ABMultiValueRef
let countOfPhones = ABMultiValueGetCount(phones)
for index in 0..<countOfPhones{
let unmanagedPhone = ABMultiValueCopyValueAtIndex(phones, index)
let phone: String = Unmanaged.fromOpaque(
unmanagedPhone.toOpaque()).takeUnretainedValue() as NSObject as String
println(phone)
}
}
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