在数据列表中的ModelPopup的Acees TaxtBox值

本文介绍了在数据列表中的ModelPopup的Acees TaxtBox值的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我有一个ModelPopup&弹出面板中有一个Datalist-Itemtemplate.
弹出面板包含TextBox，OkButton和CancelButton.
我需要从Ok-Button上的上述TextBox中获取输入，请点击
到我的鳕鱼背后进行进一步处理.
-------------------------------------------------- ------------

I have a ModelPopup & Popup-panel wihtin a Datalist-Itemtemplate.
Popup-panel contains TextBox, OkButton and CancelButton.
I need to get the input from the above TextBox on Ok-Button click
to my cod-behind for further processing.
--------------------------------------------------------------

<script type ="text/javascript" >
        function forOkbtn() 
	{
            //$find('panel_Popup').hide();//1st Problem :Javascript unable to find the control panel_Popup
            $get('DummyButton').click();//Redirect to click event of dummy-Asp:Button which outside of Datalist
        }
</script>

-------------------------------------------------- ---------------
//后面的代码

-----------------------------------------------------------------
//Code behind

protected void DummyButton_Click(object sender, EventArgs e)
    {
        TextBox popupTxt = (TextBox)DataList1.FindControl("ModelTxt");//2nd Problem :Unable to find the TextBox: ModelTxt
        String PopupTextBoxValue = popupTxt.Text;
    }

-------------------------------------------------- -----------------
我知道这不是正确的方法.期待更直接的方法或在上面的代码中建议更正

-------------------------------------------------------------------
I know this is not a right way. Expecting a more straight forward way Or Suggest Correction in the above code

推荐答案

-------------------------------------------------- ---------------
//后面的代码

-----------------------------------------------------------------
//Code behind

protected void DummyButton_Click(object sender, EventArgs e)
    {
        TextBox popupTxt = (TextBox)DataList1.FindControl("ModelTxt");//2nd Problem :Unable to find the TextBox: ModelTxt
        String PopupTextBoxValue = popupTxt.Text;
    }

-------------------------------------------------- -----------------
我知道这不是正确的方法.期待更直接的方法或在上面的代码中建议更正

-------------------------------------------------------------------
I know this is not a right way. Expecting a more straight forward way Or Suggest Correction in the above code

protected void DataList1_ItemDataBound(object sender, DataListItemEventArgs e)
        {
            switch (e.Item.ItemType)
            {
                case ListItemType.AlternatingItem:
                case ListItemType.Item:
                    Button btn = (Button)e.Item.FindControl("DummyButton");
                    TextBox txt = (TextBox)e.Item.FindControl("ModelTxt");

                    btn.Attributes.Add("onclick", "alert('" + txt.Text + "'); return false;");
                    break;
            }
        }

谢谢，
Imdadhusen

Thanks,
Imdadhusen

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