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问题描述
0
我想读取2个文本文件(Byte2.txt和FB.txt),但我不想把路径放在脚本,我想在从命令行运行脚本到解析脚本路径时使用参数。我的命令,当我从命令行运行脚本时:
$ PowerShell.exe Script.ps1 arg1 arg2
arg1表示Byte.txt的路径,arg2表示路径FB.txt
我尝试过:
< pre>
$ file = $ Args [0]
$ Data = $ Args [1]
$ file_2 = Get-Content
$ file_2
$ Data_2 = Get -content
$ Data_2
我从cmd执行该脚本:
$ PS.exe Script.ps1 C:\ User \ Pyt.txt C:\ User \ NF.txt
解决方案
0 I want to read a 2 of text file (Byte2.txt and FB.txt), but I dont want to put the path on the script, I want to use argument when I run the script from command line to parsing the path to my script. My expextation, when I run the script from command line : $PowerShell.exe Script.ps1 arg1 arg2 arg1 represent the path of Byte.txt and arg2 represent the path of FB.txt What I have tried: <pre> $file = $Args[0] $Data = $Args [1] $file_2 = Get-Content " " $file_2 $Data_2 = Get-content " " $Data_2
I execute that script from cmd :
$PS.exe Script.ps1 C:\User\Byte.txt C:\User\FB.txt
解决方案
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