问题描述
//Visual Studio 2008 sp 1
当我使用GetContextMenuManager()-> ShowPopupMenu()时，它避免了子菜单的状态.
//ShowPopupMenu(HMENU hmenuPopup，int x，int y，CWnd * pWndOwner，BOOL bOwnMessage = FALSE，BOOL bAutoDestroy = TRUE，BOOL bRightAlign = FALSE);
示例源代码
CMenu menu1，menu2;
menu.CreatePopupMenu();
menu1.AppendMenu(MF_STRING | MF_CHECKED ，WM_USER + 1，_T("A"));
menu2.AppendMenu(MF_STRING | MF_CHECKED ，WM_USER + 2，_T("SubMenu A"));
menu1.AppendMenu(MF_BYCOMMAND | MF_STRING | MF_POPUP，reinterpret_cast< uint_ptr>(menu2.Detach())，_T("Submenu"));
theApp.GetContextMenuManager()-> ShowPopupMenu(menu1.Detach()，x，y，this，TRUE，TRUE);
出现时，选中菜单"A"，但没有选中子菜单A.
没有人知道为什么吗?
//Visual Studio 2008 sp 1
when I use GetContextMenuManager()->ShowPopupMenu(), it avoid submenu''s uistate.
//ShowPopupMenu(HMENU hmenuPopup, int x, int y, CWnd* pWndOwner, BOOL bOwnMessage = FALSE, BOOL bAutoDestroy = TRUE, BOOL bRightAlign = FALSE);
Example source code
CMenu menu1, menu2;
menu.CreatePopupMenu();
menu1.AppendMenu( MF_STRING | MF_CHECKED, WM_USER+1, _T("A") );
menu2.AppendMenu( MF_STRING | MF_CHECKED, WM_USER+2, _T("SubMenu A") );
menu1.AppendMenu( MF_BYCOMMAND | MF_STRING | MF_POPUP, reinterpret_cast<uint_ptr>(menu2.Detach()), _T("Submenu") );
theApp.GetContextMenuManager()->ShowPopupMenu(menu1.Detach(), x, y, this, TRUE, TRUE);
when it appeared, the menu "A" is checked, but SubMenu A wasn''t.
isn''t there anyone know why?
推荐答案
void CMFCToolBarMenuButton::CreateFromMenu(HMENU hMenu)
确实会产生子选单，但无法控制内部的检查状态...
您可以直接插入按钮(很简单)，
或在创建呈现的种类后重新访问某些按钮:)
does produce a submenu, but does not control the checked state inside...
You could insert your buttons directly (it''s easy),
or reaccess some buttons after the creating of presented kind :)
这篇关于为什么CMFCPopupMenu避免submeu的状态?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！