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问题描述
如何将12345.12346f的浮点值转换为二进制值的字符串,即0011010101010101,反之亦然?
解决方案我不确定这是你想要的,但这里有一个解决方案,以浮点的IEEE 754浮点双格式位布局的二进制表示(它基本上是一个float):
int intBits = Float.floatToIntBits(yourFloat);
String binary = Integer.toBinaryString(intBits);
反向过程:
int intBits = Integer.parseInt(myString,2);
float myFloat = Float.intBitsToFloat(intBits);
How do I convert the float value of 12345.12346f to a String of binary values, i.e. "0011010101010101", and vice-versa?
解决方案
I'm not sure it is what you want, but here's a solution to have the binary representation of the IEEE 754 floating-point "double format" bit layout for a float (it is basically the memory representation of a float) :
int intBits = Float.floatToIntBits(yourFloat);
String binary = Integer.toBinaryString(intBits);
For the reverse procedure :
int intBits = Integer.parseInt(myString, 2);
float myFloat = Float.intBitsToFloat(intBits);
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09-15 04:49