问题描述
我有一个引发异常的Mlflow项目.我使用 mlflow.run 执行该功能，但是却得到 mlflow.exceptions.ExecutionException(运行失败(ID'< run_id>')失败").
I have an Mlflow project that raises an exception. I execute that function using mlflow.run, but I get mlflow.exceptions.ExecutionException("Run (ID '<run_id>') failed").
在执行 mlflow.run 时，有什么办法可以获取正在引发的异常吗?
Is there any way I could get the exception that is being raised where I am executing mlflow.run?
或者是否可以从项目内部发送带有自定义消息集的 mlflow.exceptions.ExecutionException ?
Or is it possible to send an mlflow.exceptions.ExecutionException with custom message set from within the project?
推荐答案
不幸的是目前不在.mlflow run启动一个新进程，并且目前没有用于异常传递的协议.通常，其他项目甚至不必使用相同的语言.
Unfortunately not at the moment. mlflow run starts a new process and there is no protocol for exception passing right now. In general the other project does not even have to be in the same language.
我能想到的一种解决方法是通过设置运行标签通过mlflow传递异常.例如:
One workaround I can think of is to pass the exception via mlflow by setting run tag. E.g.:
try:
...
except Exception as ex:
mlflow.set_tag("exception", str(ex))
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