本文介绍了扭转词串词的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我能够扭转的字符串。例如,我可以扭转反向字符串到esrever一个gnirts。但我不能够通过文字来扭转它像字字符串反向。

 无效reverseString(字符字符串[],字符*开始,字符*完)
{    焦炭TMP; //临时变量来交换值
    诠释计数= 0;
    同时(开始与LT端)
    {
        如果(*开始=='')
        {
            的printf(发现空间计数%d个\\ N算);
            reverseString(字符串,开始计数,启动);
        }
        TMP = *启动;
        *开始= *结束;
        *结束= tmp目录;
        *启动++;
        *结束 - ;
        算上++;
    }    的printf(字符串%S \\ n,字符串);
}诠释的main()
{
    字符字符串[] =扭转词串词;
    字符*开始=字符串;
    字符*年底开始= strlen的+(字符串)-1;
    reverseString(字符串,开始,结束);
    返回0;
}


解决方案

这是这样的。我能够扭转串字为单位,以及整个字符串。刚刚经过code,看看逻辑有所帮助。

 的#include<&stdio.h中GT;
#包括LT&;&string.h中GT;无效stringrev(字符*);
无效reverseWords(字符*);
无效reverseString(字符*,INT);诠释的main()
{    字符字符串[] =扭转词串词;
    reverseWords(字符串);
    的printf(\\ nWord英明反转字符串:%S \\ n,字符串);
    stringrev(字符串);
    返回0;}无效reverseWords(字符*海峡)
{
    INT I = 0,J = 0;
    reverseString(STR,strlen的(STR));
    而(1)//死循环
    {
        如果(*(STR + J)==''|| *(STR + J)=='\\ 0')//找到的单词或达到句子的末尾
        {
            reverseString(STR + I,J-I);
            I = J + 1;
        }
        如果(*(STR + J)=='\\ 0')
        {
            打破;
        }
        J ++;
    }
}无效reverseString(的char * str中,INT LEN)
{
    INT I,J;
    焦温度;
    I = J =温度= 0;    J = LEN-1;
    对于(i = 0; I<焦耳;我++,j--)
    {
        TEMP = STR [I]
        海峡[I] = STR [J]。
        海峡[J] =温度;
    }
}无效stringrev(字符*海峡)
{
    INT I = -1,J = 0;
    字符转[50];    而(STR [我++] ='\\ 0'!);        而(ⅰ> = 0)
         转[J ++] = STR [我 - ]    转[J] ='\\ 0';    的printf(字符串的\\ nComplete相反的情况:%S \\ n,REV);
}

I am able to reverse a string. For example, I can reverse "reverse a string" to "esrever a gnirts". But I am not able to reverse it word by word like "string a reverse".

void reverseString(char string[],char *start, char* end)
{

    char tmp; //temporary variable to swap values
    int count = 0;
    while(start<end)
    {
        if(*start==' ')
        {
            printf("found space count %d \n",count);
            reverseString(string,start-count,start);
        }
        tmp = *start;
        *start = *end;
        *end = tmp;
        *start++;
        *end--;
        count++; 
    }

    printf(" string %s \n", string); 
}

int main()
{
    char string[] = "reverse a string word by word";
    char *start =string;
    char *end =start+ strlen(string) -1;
    reverseString(string,start,end);
    return 0;
}
解决方案

This is the way. I am able to reverse a string word-wise, as well as the entire string. Just go through the code and see if the logic helps.

#include <stdio.h>
#include <string.h>

void stringrev(char *);
void reverseWords(char *);
void reverseString(char* , int);

int main()
{

    char string[] = "reverse a string word by word";
    reverseWords(string);
    printf("\nWord-Wise Reversed String : %s\n",string);
    stringrev(string);
    return 0;

}

void reverseWords(char * str)
{
    int i = 0, j = 0;
    reverseString( str, strlen(str) ); 
    while( 1 ) // Loop forever
    {
        if( *(str+j) == ' ' || *(str+j) == '\0') // Found a word or reached the end of sentence
        {
            reverseString( str+i, j-i );
            i = j+1;
        }
        if( *(str+j) == '\0')
        {
            break;
        }
        j++;
    }
}

void reverseString(char* str, int len)
{
    int i, j;
    char temp;
    i=j=temp=0;

    j=len-1;
    for (i=0; i<j; i++, j--)
    {
        temp=str[i];
        str[i]=str[j];
        str[j]=temp;
    }
}

void stringrev(char *str)
{
    int i=-1,j=0;
    char rev[50];

    while(str[i++]!='\0');

        while(i>=0)
         rev[j++] = str[i--];

    rev[j]='\0';

    printf("\nComplete reverse of the string is : %s\n",rev);    
}

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09-20 23:25