如何为序列化程序分页queryset

问题描述

我正在检索Category及其outfits列表.我的问题是outfits属于category的太多.

I'm retreiving Category and its outfits list. My problem is there are too many outfits belong to a category.

class CategoryListAPIView(generics.RetrieveAPIView):
    serializer_class = CategoryDetailSerializer
    ...

class CategoryDetailSerializer(serializers.ModelSerializer):
    outfits = serializers.SerializerMethodField()
    ...

    class Meta:
        model = Category
        fields = (
            ...
            'outfits',
            ...
        )

    def get_outfits(self, obj):  //This is returning 39 items. 
        // Can we paginate this? 
        if obj.outfits is not None:
            return OutfitListSerializer(obj.outfits, many=True).data
        return None

我们可以对它进行分页，以便用户首先看到24个outfits并刷新以查看其余的outfits吗?

Can we paginate it so that user can first see 24 outfits and refresh to see the rest of outfits?

推荐答案

如果您想要简单的条件前24个"和其余".您可以通过获取参数来控制它.

If you want simple condition "first 24" and "the rest". You could control it by get parameters.

def get_outfits(self, obj):
    show_all = self.request.GET.get('show_all')

    if show_all:
        outfits = obj.outfits.all()
    else:
        outfits = obj.outfits.all()[:24]

    return OutfitListSerializer(outfits, many=True).data

现在，您可以将GET /categories/用于前24套服装的类别，而将GET /categories/?show_all=true用于全面展示

Now you can use GET /categories/ for categories with first 24 outfits and GET /categories/?show_all=true for full representation

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