不可行的行为

再见， 快点。Hi,In my piece of code I see some unprectable behaviour for simplefunctions like for example pow() function in math.h returns, -1#IND0for simple arguments like POW( (double) 1, (double) 2 ) andarbitrarily even some simple multiplication seem to return the same,-1#IND0 ( in debugging mode, individual variables have correct valuesbut final product is undefined).I was trying to solve this and in the process, found a wierd soltn, onjust repeating the same line again gives the correct result.TIAbye,hurry.推荐答案" hurry" <胡********* @ gmail.com>写道："hurry" <hu*********@gmail.com> wrote:在我的代码片段中，我看到一些简单的行为，例如math.h中的pow（）函数返回，-1＃IND0 任意甚至一些简单的乘法似乎返回相同， -1＃IND0（在调试模式下，个别变量有正确的值但是最终产品是未定义的。 In my piece of code I see some unprectable behaviour for simple functions like for example pow() function in math.h returns, -1#IND0 for simple arguments like POW( (double) 1, (double) 2 ) and arbitrarily even some simple multiplication seem to return the same, -1#IND0 ( in debugging mode, individual variables have correct values but final product is undefined). 狂野的猜测......你还记得#include< math.h>？ RichardWild guess... did you remember to #include <math.h>?Richard是的我做了yup I did hurry写道：hurry wrote: 在我的代码片段中，我看到一些简单的行为，例如pow（）函数等简单的函数在math.h返回，-1＃IND0 对于简单的参数如POW（（double）1，（double）2）和任意甚至一些简单的乘法似乎返回sam e， -1＃IND0（在调试模式下，个别变量具有正确的值但最终产品未定义）。 我试图解决这个问题并在此过程中，发现了一个奇怪的解决方案，只是重复相同的行再次给出正确的结果。 再见，快点。 Hi, In my piece of code I see some unprectable behaviour for simple functions like for example pow() function in math.h returns, -1#IND0 for simple arguments like POW( (double) 1, (double) 2 ) and arbitrarily even some simple multiplication seem to return the same, -1#IND0 ( in debugging mode, individual variables have correct values but final product is undefined). I was trying to solve this and in the process, found a wierd soltn, on just repeating the same line again gives the correct result. TIA bye, hurry. 您能否发布您的代码？Could you please post your code ? 这篇关于不可行的行为的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！