本文介绍了在 Dijit AccordionContainer 中以编程方式打开窗格的最佳方法是什么的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试打开 &以编程方式关闭手风琴窗格.这是我的代码的简化版本.即使我将第一个窗格的选择设置为 false,将第二个窗格的选择设置为 true,但在浏览器 (FF3) 上加载时,只有第一个窗格会打开.

I am trying open & close accordion panes programatically. Here is the simplified version of my code. Even though I set the first pane's selected to false and and second pane's selected to true, only the first pane opens when it loads on the browser (FF3).

var accordionContainer = new dijit.layout.AccordionContainer().placeAt("test");
var accordPane = new dijit.layout.ContentPane({"title": "test", "content":"hello"});
var accordPane2 = new dijit.layout.ContentPane({"title": "test1", "content":"hello1"});
accordionContainer.addChild(accordPane);
accordionContainer.addChild(accordPane2, 1);
accordPane.startup();
accordPane2.startup();
//accordionContainer.selectChild(accordPane2);
accordionContainer.startup();
accordPane.selected = false;
accordPane2.selected = true;

推荐答案

你可以这样做:

accordionContainer.selectChild( accordPane2 );

假设您使用的是 dojo 1.3.

Assuming you are using dojo 1.3.

dijit.layout.AccordionContainerdijit.layout.StackContainer 的子类,定义了 selectChild.

dijit.layout.AccordionContainer is a subclass of dijit.layout.StackContainer, which has selectChild defined.

我设置了一个演示页面,您可以在其中看到此代码的实际效果

如果您在 startup 之前调用 selectChild,这可能会导致您看到的错误,因为小部件未处于完成"状态.(抱歉,在我发布原始答案之前错过了commneted 代码)

If you were calling selectChild before startup, that could cause the error you were seeing since the widget wasn't in a 'complete' state. (Sorry, missed the commneted out code before I posted original answer)

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10-11 23:38