问题描述
我不确定我是否会生气或愚蠢但是我可以依赖我的眼睛上的
，当我将一个元素添加到Vector时，它会被放置
所有位置，而不是最后一个位置。这就好比如果它沿着列表的方向滚动所有
一直留下它的足迹。
我写的
，如：
import java.util。*;
public class Temp {
public static void main（String [] arg）{
Vector vec = new Vector（）;
String [] outPutLine = new String [3];
String line;
for（int k = 0; k
for（int i = 0; i< outPutLine.length; i ++）
outPutLine [i ] =" S（" + i +" ;;" + k +"）" ;;
vec.add（outPutLine）;
System.out.println（" outPutLine" + k +" is：\t\t" + outPutLine [0] +
" \t" + outPutLine [ 1] +" \t" + outPutLine [2]）;
System.out.println（"结果是："）;
String test ="" ;;
for（int i = 0; i< vec.size（）; i ++）{
for（int j = 0; j
test + =（（String []）vec.get（i））[j];
test + =" \ n" ;;
}
System.out.println（test +" \\\
------------------------------ --- \ n"）;
}
}
}
所以，它只是我还是有输出的时髦？例如，
元素S（0; 0）去了哪里？！
-
请支付
Konrad
-------------------------------- -------------------
愿所有垃圾邮件发送者死于痛苦的死亡;没有埋葬地点;
他们的灵魂会被Gehenna的恶魔从一个房间追逐到
另一个永恒和更多。
睡眠 - 无效人士使用的东西
作为咖啡的替代品
野心 - 一个糟糕的借口没有
足够的感觉是懒惰的
------------------------------------- --------------
I''m not sure if i''m going mad or stupid but as far as i can rely
on my eyes, when i ADD an element to a Vector, it gets put on
ALL the position, instead of the last one. It''s like if it rolls all
the way down the list leaving its footprints along the way.
I wrote, like:
import java.util.*;
public class Temp {
public static void main (String[] arg) {
Vector vec = new Vector ();
String[] outPutLine = new String[3];
String line;
for (int k = 0; k < 4; k++) {
for (int i = 0; i < outPutLine.length; i++)
outPutLine[i] = "S(" + i + ";" + k + ")";
vec.add (outPutLine);
System.out.println ("outPutLine " + k + " is: \t\t" + outPutLine[0] +
"\t" + outPutLine[1] + "\t" + outPutLine[2]);
System.out.println ("The result is:");
String test = "";
for (int i = 0; i < vec.size (); i++) {
for (int j = 0; j < 3; j++)
test += ((String[])vec.get (i))[j];
test += "\n";
}
System.out.println (test + "\n---------------------------------\n");
}
}
}
So, is it just me or is there funky with the output? Where did the
element S(0;0) go, for instance?!
--
Kindly
Konrad
---------------------------------------------------
May all spammers die an agonizing death; have no burial places;
their souls be chased by demons in Gehenna from one room to
another for all eternity and more.
Sleep - thing used by ineffective people
as a substitute for coffee
Ambition - a poor excuse for not having
enough sense to be lazy
---------------------------------------------------
推荐答案
用S（0; 1）覆盖它。
建议：移动作业outPutLine = new String [3];"在
" for（int k ...）中环。这样你就可以创建四个String [3]，
，如果你想存储12个单独的字符串，这很有用......
Mut ，
克里斯
-
Chris Gray
/ k /嵌入式Java解决方案
You overwrote it with S(0;1).
Suggestion: move the assignment "outPutLine = new String[3];" inside the
"for (int k ...)" loop. That way you will be creating four String[3]''s,
which is useful if you want to store 12 separate strings ...
Mut,
Chris
--
Chris Gray ch***@kiffer.eunet.be
/k/ Embedded Java Solutions
这篇关于java.util.Vector的奇怪行为的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！