问题描述
我通过Sprite Kit进入iOS,我认为这是不明智的。
I'm entering iOS via Sprite Kit, which I recognize is unwise.
我的目标是在游戏结束时显示分享按钮。点击共享按钮应该呈现SLComposeViewController(Twitter共享)。场景的内容不应该改变。
My goal is to display a "Share" button upon Game Over. Tapping the share button should present a SLComposeViewController (Twitter Share). The contents of the scene should not change.
决定游戏结束的游戏逻辑存在于SpriteMyScene.m中,这是SKScene的子类。
The game logic that dictates "Game Over" lives in SpriteMyScene.m, a subclass of SKScene.
我可以通过这种方式在Game上显示一个Share按钮:
I'm able to display a Share button on Game Over this way:
-(void)update:(CFTimeInterval)currentTime {
if (gameOver){
UIButton *button = [UIButton buttonWithType:UIButtonTypeRoundedRect];
[button addTarget:self
action:@selector(sendToController)
forControlEvents:UIControlEventTouchDown];
[button setTitle:@"Show View" forState:UIControlStateNormal];
button.frame = CGRectMake(80.0, 210.0, 160.0, 40.0);
[self.view addSubview:button];
}
}
- (void)sendToController
{
NSLog(@"ok");
SpriteViewController *viewController = [SpriteViewController alloc];
[viewController openTweetSheet];
}
我遇到的问题是试图让showTweetButton方法起作用。我的SpriteViewController.m如下所示:
Where I get stuck is trying to get the showTweetButton method to work. My SpriteViewController.m looks like this:
- (void)openTweetSheet
{
SLComposeViewController *tweetSheet = [SLComposeViewController
composeViewControllerForServiceType:
SLServiceTypeTwitter];
// Sets the completion handler. Note that we don't know which thread the
// block will be called on, so we need to ensure that any required UI
// updates occur on the main queue
tweetSheet.completionHandler = ^(SLComposeViewControllerResult result) {
switch(result) {
// This means the user cancelled without sending the Tweet
case SLComposeViewControllerResultCancelled:
break;
// This means the user hit 'Send'
case SLComposeViewControllerResultDone:
break;
}
};
// Set the initial body of the Tweet
[tweetSheet setInitialText:@"just setting up my twttr"];
// Adds an image to the Tweet. For demo purposes, assume we have an
// image named 'larry.png' that we wish to attach
if (![tweetSheet addImage:[UIImage imageNamed:@"larry.png"]]) {
NSLog(@"Unable to add the image!");
}
// Add an URL to the Tweet. You can add multiple URLs.
if (![tweetSheet addURL:[NSURL URLWithString:@"http://twitter.com/"]]){
NSLog(@"Unable to add the URL!");
}
// Presents the Tweet Sheet to the user
[self presentViewController:tweetSheet animated:NO completion:^{
NSLog(@"Tweet sheet has been presented.");
}];
}
我总是在日志中得到这样的信息:
I always get something like this in the logs:
推荐答案
您正在创建一个新的视图控制器,但从不提供它:
You're creating a new view controller but never presenting it:
SpriteViewController *viewController = [SpriteViewController alloc];
我假设 SpriteViewController
是什么出现你的 SpriteMyScene
,你想把控制权交还给现在的 SpriteViewController
。
I'm assuming that SpriteViewController
is what presents your SpriteMyScene
, and you'd like to hand control back to the presenting SpriteViewController
.
您需要在 SpriteMyScene
子类中保留对 SpriteViewController
的引用,然后在SpriteMyScene.h中调用 openTweetSheet
。
You need to keep a reference to SpriteViewController
in your SpriteMyScene
subclass, and then access that reference when you call openTweetSheet
.
时访问该引用
@class SpriteViewController;
@interface SpriteMyScene : SKScene
@property (nonatomic, weak) SpriteViewController *spriteViewController;
@end
SpriteViewController.m中的
in SpriteViewController.m
// somewhere you initialize your SpriteMyScene object, I'm going to call it myScene
myScene.spriteViewController = self;
SpriteMyScene.m中的
in SpriteMyScene.m
#import "SpriteViewController.h"
- (void)sendToController
{
NSLog(@"ok");
// use the already-created spriteViewController
[_spriteViewController openTweetSheet];
}
这篇关于如何从SKScene呈现UIViewController?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!