查找 RotatedRect 的宽度和高度

问题描述

请参阅 此 C++ 代码for 循环以查找 aspect_ratio.我没有得到任何线索来获得 RotatedRect 的最小值和最大值 宽度和高度在 Python 中作为 C++ 的 RotatedRect 的替代，python 中的 strong> 是 cv2.boxPoints

Refer to This C++ code I am trying to change in python to do the exact same thing but I am stuck at for loop to find aspect_ratio. I am not getting any clue to get the minimum and maximum width and height of RotatedRect in python as an alternate to RotatedRect of C++ in Python is cv2.boxPoints

import cv2
from matplotlib import pyplot as plt
img = cv2.imread('C:/Users/Zeeesh/Desktop/1.jpg', cv2.IMREAD_GRAYSCALE)
ret,thresh = cv2.threshold(img,200,255,0)
img1,contours, hierarchy = cv2.findContours(thresh,cv2.RETR_TREE,cv2.CHAIN_APPROX_NONE)
out = cv2.cvtColor(img, cv2.COLOR_GRAY2BGR)
for contour in contours:
    rect = cv2.minAreaRect(contour)
    (x, y), (width, height), angle = rect
    aspect_ratio = min(width, height) / max(width, height)

    thresh1 = 0.2
    if (aspect_ratio > thresh1):
        print('Straight Line')
        for pt in contour:
            cv2.drawContours(out, [pt], 0,255,0)
    else:
        print('Curve')
        for pt in contour:
            cv2.drawContours(out, [pt], 0,0,255)






plt.imshow(out)

推荐答案

你可以找到旋转矩形的width和height:

You can find width and height of the rotated rect with:

rect = cv2.minAreaRect(contour)
(x, y), (width, height), angle = rect

那么纵横比为:

aspect_ratio = min(width, height) / max(width, height)

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