问题描述
好的，现在我需要打开一个表单（frmTopics）并选择在单独的表单中双击的相同记录（frmTopicsFound）。以下是详细信息：
frmTopicsFound包含数据表子表单sfrmTopicsFound。 sfrmTopicsFound是从查询中填充的，该查询根据关键字搜索返回主题列表。我希望用户能够双击sfrmTopicsFound中的一行并将frmTopics打开到同一记录。 frmTopics可能已经或可能没有开放。
基本上，我需要在sfrmTopicsFound.nbrTopID的OnDlbClick事件上使用一些代码：
1.打开frmTopics，如果它还没有打开
2.显示来自tblTopics的记录，其中tblTopics.topID = Forms！sfrmTopicsFound！nbrTopID
我确定已经这样做了，如果有人能指出我的一些示例代码，也许我可以从那里拿走它。谢谢！
Okay, now I need to open a form (frmTopics) and select the same record that has been double-clicked on in a separate form (frmTopicsFound). Here are the details:
frmTopicsFound contains datasheet subform sfrmTopicsFound. sfrmTopicsFound is populated from a query that returns a list of topics based on a keyword search. I want users to be able to double-click a row in sfrmTopicsFound and have frmTopics open to that same record. frmTopics may or may not not be open already.
So basically, I need some code on the OnDlbClick event for sfrmTopicsFound.nbrTopID that will:
1. Open frmTopics if it''s not already open
2. Display the record from tblTopics where tblTopics.topID = Forms!sfrmTopicsFound!nbrTopID
I''m sure this has been done so if anyone could point me to some sample code, maybe I can take it from there. Thanks!
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