本文介绍了请帮我看看这个“插入数据库”并进行更正。尽快的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
使用系统;
使用 System.Collections.Generic;
使用 System.Linq;
使用 System.Web;
使用 System.Web.UI;
使用 System.Web.UI.WebControls;
使用 System.Data.SqlClient;
使用 System.Configuration;
使用 System.Data;
public partial class Default7:System.Web.UI.Page
{
protected void Page_Load( object sender,EventArgs e)
{
}
protected void Button1_Click( object sender,EventArgs e)
{
if (!FileUpload1.HasFile) // 验证
{
Response.Write( No file Selected ); 返回;
}
else
{
string filename = FileUpload1.PostedFile.FileName;
// 将图像转换为字节
byte [] imageByte = System.IO.File.ReadAllBytes(filename);
// 在表格中插入数据
using (SqlConnection connection = new SqlConnection())
{
connection.ConnectionString = ConfigurationManager .ConnectionStrings [ lateefconnectionstring]。ToString();
connection.Open();
SqlCommand cmd = new SqlCommand();
cmd.Connection = connection;
string commandText = 插入用户值(@ Surname,@ Lastame,@ username,@ Phone,@ image,getdate,@ Department());
cmd.CommandText = commandText;
cmd.CommandType = CommandType.Text;
cmd.Parameters.Add( @ Surname,SqlDbType.VarChar);
cmd.Parameters [ @ Surname]。Value = TxtSurname.Text;
cmd.Parameters.Add( @ Lastame,SqlDbType.VarChar);
cmd.Parameters [ @ Lastame]。Value = TxtLastName.Text;
cmd.Parameters.Add( @ username,SqlDbType.VarChar);
cmd.Parameters [ @ username]。Value = TxtUsername.Text;
cmd.Parameters.Add( @ Phone,SqlDbType.VarChar);
cmd.Parameters [ @ Phone]。Value = TxtPhone.Text;
cmd.Parameters.Add( @ image,SqlDbType.VarBinary);
cmd.Parameters [ @ image]。Value = imageByte;
cmd.Parameters.Add( @ Department,SqlDbType.VarChar);
cmd.Parameters [ @ Department]。Value = TxtDpt.Text;
cmd.ExecuteNonQuery();
cmd.Dispose();
connection.Close();
Response.Write( 已添加数据);
}
}
}
}
解决方案
using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using System.Data.SqlClient; using System.Configuration; using System.Data; public partial class Default7 : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { } protected void Button1_Click(object sender, EventArgs e) { if (!FileUpload1.HasFile) //Validation { Response.Write("No file Selected"); return; } else { string filename = FileUpload1.PostedFile.FileName; //convert the image into the byte byte[] imageByte = System.IO.File.ReadAllBytes(filename); //Insert the Data in the Table using (SqlConnection connection = new SqlConnection()) { connection.ConnectionString = ConfigurationManager.ConnectionStrings["lateefconnectionstring"].ToString(); connection.Open(); SqlCommand cmd = new SqlCommand(); cmd.Connection = connection; string commandText = "Insert into users values (@Surname,@Lastame,@username,@Phone,@image,getdate,@Department())"; cmd.CommandText = commandText; cmd.CommandType = CommandType.Text; cmd.Parameters.Add("@Surname", SqlDbType.VarChar); cmd.Parameters["@Surname"].Value = TxtSurname.Text; cmd.Parameters.Add("@Lastame", SqlDbType.VarChar); cmd.Parameters["@Lastame"].Value = TxtLastName.Text; cmd.Parameters.Add("@username", SqlDbType.VarChar); cmd.Parameters["@username"].Value = TxtUsername.Text; cmd.Parameters.Add("@Phone", SqlDbType.VarChar); cmd.Parameters["@Phone"].Value = TxtPhone.Text; cmd.Parameters.Add("@image", SqlDbType.VarBinary); cmd.Parameters["@image"].Value = imageByte; cmd.Parameters.Add("@Department", SqlDbType.VarChar); cmd.Parameters["@Department"].Value = TxtDpt.Text; cmd.ExecuteNonQuery(); cmd.Dispose(); connection.Close(); Response.Write("Data has been Added"); } } } }
解决方案
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