需要帮助制作我的第一个Java代码。 （硬币变化）

问题描述

我的作业要求我读取用户输入的数字并输出数字所产生的硬币。例如，如果用户输入37，则程序应响应（1 1/4，1和1便士）。我最有可能的代码根本没有任何意义，我不知道我需要做些什么来修复它。

My assignment requires me to read a number entered by the user and output the coins that number makes. For example, if the user enters "37", the program should respond with (1 Quarter, 1 dime, and 2 pennies). The code I have most likely does not make any sense at all and I don't know what I need to do to fix it.

import java.util.Scanner;

public class Change
{
    public static void main(String[] args)
    {
        Scanner sc = new Scanner (System.in);
        Int n = sc.nextInt("Enter a positive integer" );
        int number1, number2; // Division operands
        int quotient;         // Result of division


            if (QtrCnt > 0)
                if (QtrCnt > 1)
                    System.out.println(QtrCnt + " quarters");
                else
                    System.out.println(QtrCnt + " quarter");
        }

        if (DimeCnt > 0)
        {
            if (DimeCnt > 1)
                System.out.println(DimeCnt + " dimes");
            else
                System.out.println(DimeCnt + " dime");
        }

        if (NicklCnt > 0)
        {
            if (NicklCnt > 1)
                System.out.println(NicklCnt + " nickles");
            else
                System.out.println(NicklCnt + " nickle");
        }

        if (PennyCnt > 0);
        {
            if (PennyCnt > 1);
                System.out.println(PennyCnt + " pennies");
            System.out.println(PennyCnt + " penny");
        }

        int q = 25;
        int d = 10;
        int n = 5;
        int p = 1;

        if (a < 0);
            System.out.println("ERROR");


            String (money >=25); { int numQuarters = money/ 25; }
            money -= numQuarters * 25;
            QtrCnt = (num1 - num1 % 25) / 25;
            num1 = num1 - QtrCnt * 25;

            String(money >=10); { int numDimes = money/ 10; }
            money -= numDimes * 10;
            DimeCnt = (num1 - num1 % 10) / 10;
            num1 = num1 - DimeCnt * 10;

            String (money >=5); { int numNickles = money/ 5; }
            money -= numNickles * 5;
            NicklCnt = (num1 - num1 % 5) / 5;
            num1 = num1 - NicklCnt * 5;

            String (money >=1); { int numPennies = money/ 1; }
            money -= numPennies * 1;
            PennyCnt = (num1 - num1 % 1) / 1;
            num1 = num1 - PennyCnt * 1;
        }
   }
 }

推荐答案

划分和下限（你应该重新开始）

Divide and floor (you should probably start over)

public static int getQuarters(int cents) {
    return Math.floor(cents / 25.0);
}

以下是您的工作方式：

public static void main(String[] args) {
    int cents = 46; // 46 just for an example
    int left = cents; // a variable that represents how many cents are left
    int quarters = getQuarters(cents); // how many quarters fit into 46 (1)
    int left -= quarters * 25; // now we have 21 cents left we need to work out
    int dimes = getDimes(left); // you can implement getDimes yourself (look at getQuarters). This will now return 2, since 2 dimes can go into 21 cents.
    left -= dimes * 10; // we now have only 1 cent to account for
    int nickels = getNickels(left) // Returns 0 (no nickels can fit into 1 cent)
    left -= nickels * 5; // we still have 1 cent left
    int pennies = left; // how many pennies are left over (always < 5)
    System.out.println(cents + " cents = " + quarters + " Quarters, " + dimes + " Dimes, " + nickels + " Nickels, and " + pennies + " Pennies."); // print the output
}

请记住在Java类中包含getQuarters方法

Remember to include the getQuarters method in your Java class

示例：

• getQuarters（25） - > ; 1


• getQuarters（24） - > 0


• getQuarters（49） - > 1


• getQuarters（51） - > 2

• getQuarters(25) -> 1
• getQuarters(24) -> 0
• getQuarters(49) -> 1
• getQuarters(51) -> 2

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